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Olegator [25]
3 years ago
10

Which of the following is best described by the term macroscopic?

Chemistry
1 answer:
n200080 [17]3 years ago
4 0

Answer:

A

Explanation:

Since macroscopic means visible to the naked eye without a microscope it would be A. This is because we can see active phase changes in real time without any magnification like water boiling or ice melting.

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3 H2 (g) + N2 (g) 2 NH3 (g)
ale4655 [162]

Answer:

Mass = 0.697 g

Explanation:

Given data:

Volume of hydrogen = 1.36 L

Mass of ammonia produced = ?

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

3H₂ + N₂       →      2NH₃

First of all we will calculate the number of moles of hydrogen:

PV  = nRT

R = general gas constant = 0.0821 atm.L/mol.K

1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K

1.36 atm.L = n × 22.43 atm.L/mol

n = 1.36 atm.L / 22.43 atm.L/mol

n = 0.061 mol

Now we will compare the moles of hydrogen and ammonia:

                 H₂         :          NH₃

                  3          :            2

                0.061     :         2/3×0.061 = 0.041

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.041 mol × 17 g/mol

Mass = 0.697 g

4 0
3 years ago
Why is melting an ice cube a reversible physical change?
Dmitriy789 [7]

Answer:

Because you can freeze the water you melted back into a ice cube.

Explanation:

7 0
3 years ago
A rigid vessels contains
EleoNora [17]
Hope this helps you.

3 0
3 years ago
Anton van Leeuwenhoek used a microscope to observe
Goshia [24]
B. He was the first person to observe and identify living cells.
4 0
3 years ago
PLZ HELP For the reaction: 2NO2(g) → N2O4(l),
Furkat [3]

Answer: \Delta H_{rxn}=-20kJ/mol-(+66kJ/mol)

Explanation:

Heat of reaction or enthalpy change is the energy released or absorbed during the course of the reaction.

It is calculated by subtracting the enthalpy of reactants from the enthalpy of products.

\Delta H=H_{products}-H_{reactants}

\Delta H = enthalpy change = ?

H_{products} = enthalpy of products

H_{reactants} = enthalpy of reactants

For the given reaction :

2NO_2(g)\rightarrow N_2O_4(l)

\Delta H=H_{N_2O_4}-2\times H_{NO_2}

\Delta H=-20kJ/mol-(+66kJ/mol)

6 0
3 years ago
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