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Zina [86]
2 years ago
6

When the methanol is ignited, what other reactant is involved in the reaction?.

Chemistry
1 answer:
babymother [125]2 years ago
7 0
Oxygen has to be involved when methanol is ignited
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Which of the following represents an electron configuration that corresponds to the valence electrons of an element for which th
Mademuasel [1]

The electron configuration that corresponds to the valence electrons of an element for which there is an especially large jump between the second and third ionization energies is ns^2.

The valence electron configuration of an atom refers to the arrangement of electrons on the outermost shell of the atom.

Recall that a large jump in ionization energy occurs when electrons are removed from inner shells of the atom.

If we study our options closely, we will discover that option A has only two electrons in the valence shell (ns^2).

This means that the third ionization energy involves removing electrons from an inner shell which leads to large jump.

Learn more: brainly.com/question/14283892

6 0
3 years ago
Read 2 more answers
At night, the Moon appears bright. Which of the following explains this?
Lady bird [3.3K]
The answer is
<span>a. The Moon reflects the light produced by the Sun.</span>
6 0
3 years ago
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K = °C + 273 A 4.1 L sample of gas is held at 25 °C. If the gas expands to 6.8 L, what is the final temperature?
gregori [183]

Answer:

221 °C

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 4.1 L

Initial temperature (T₁) = 25 °C

= 25 °C + 273

= 298 K

Final volume (V₂) = 6.8 L

Final temperature (T₂) =?

The final temperature of the gas can be obtained as follow:

V₁ / T₁ = V₂ / T₂

4.1 / 298 = 6.8 / T₂

Cross multiply

4.1 × T₂ = 298 × 6.8

4.1 × T₂ = 2026.4

Divide both side by 4.1

T₂ = 2026.4 / 4.1

T₂ ≈ 494 K

Finally, we shall convert 494 K to celcius temperature. This can be obtained as follow:

°C = K – 273

K = 494

°C = 494 – 273

°C = 221 °C

Thus the final temperature of the gas is 221 °C

6 0
3 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

V_1=~?

C_2=~0.1374_M

V_2=~250.0~mL

If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
3 years ago
Does a metal conduct electricity in the solid state?
ad-work [718]
Metal atoms have outer electrons which are not tied to any one atom. These electrons can move freely within the structure of a metal when an electric current is applied. There are no such free electrons in covalent or ionic solids, so electrons can't flow through them - they are non-conductors.

In a shorter term - no
5 0
3 years ago
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