When the methanol is ignited, what other reactant is involved in the reaction?.

Periods On the periodic table represent elements

Natalka [10]

Answer:When you look at the periodic table, each row is called a period (Get it? Like PERIODic table.). All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons.

Explanation:

7 0

2 years ago

Hydroxylamine hydrochloride is a powerful reducing agent which is used as a polymerization catalyst. It contains 5.80 mass % H,

ludmilkaskok [199]

<u>Answer:</u> The empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

<u>Explanation:</u>

We are given:

Percentage of H = 5.80 %

Percentage of O = 23.02 %

Percentage of N = 20.16 %

Percentage of Cl = 51.02 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 5.80 g

Mass of O = 23.02 g

Mass of N = 20.16 g

Mass of Cl = 51.02 g

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{5.80g}{1g/mole}=5.80moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{23.02g}{16g/mole}=1.44moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{20.16g}{14g/mole}=1.44moles$

Moles of Chlorine = $\frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{51.02g}{35.5g/mole}=1.44moles$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.44 moles.

For Hydrogen = $\frac{5.80}{1.44}=4.03\approx 4$

For Oxygen = $\frac{1.44}{1.44}=1$

For Nitrogen = $\frac{1.44}{1.44}=1$

For Chlorine = $\frac{1.44}{1.44}=1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of H : O : N : Cl = 4 : 1 : 1 : 1

Hence, the empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

3 0

3 years ago

A physician has ordered 0.50 mg of atropine, intramuscularly. If atropine were available as 0.25 mg/mL of solution, how many mil

sladkih [1.3K]

If 0.25mg of atropine is in 1mL
so
0.50mg of atropine is in x

$x=\frac{0.5mg*1mL}{0.25mg}=2mL$

6 0

3 years ago

A property is a characteristic of a substance that can be observed and does not change the identity of the substance. T/F

Murljashka [212]

The correct answer is false. The statement given does not describe a property in general. However, it speaks of a specific type of property which is the physical property. This property is the one that does not change the identity of a substance. A property can also be a chemical property where the identity of a substance is changed.

4 0

2 years ago

The teacher said the volume of the liquid was 500 mL when measured a student found it was 499.7 mL what is the students percent

Natalka [10]

Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

error = 500 - 499.7 = 0.3

actual volume = 500 mL

We have

$p(\%) = \frac{0.3}{500} \times 100 \\ = \frac{3}{50} \\$

We have the final answer as

Hope this helps you

4 0

3 years ago