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inna [77]
2 years ago
14

At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume

Chemistry
1 answer:
Natalija [7]2 years ago
4 0

Answer: Volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

Explanation:

Given: T_{1} = 35^{o}C = (35 + 273) K = 308 K,     V_{1} = 256 mL,    

P_{1} = 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm

T_{1} = 22^{o}C = (22 + 273) K = 295 K,       P_{2} = 1.25 atm  

Formula used to calculate volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 256 mL}{308 K} = \frac{1.25 atm \times V_{2}}{295 K}\\V_{2} = 196.15 mL

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

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3 years ago
The surface temperatures on land vary more over the course of a year than the surface temperatures on the ocean because land has
bogdanovich [222]

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Lower heat capacity

Explanation:

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I hope you find this information useful and interesting! Good luck!

7 0
3 years ago
Please help quick<br> Alkali means ___.
sveticcg [70]

Answer:

Metal

Explanation:

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8 0
3 years ago
How much heat (in Joules) is needed to raise the temperature of 257g of ethanol (cethanol=2.4 J/g°C) by 49.1°C?
Sonbull [250]

Answer:

Q = 30284.88 j

Explanation:

Given data:

Mass of ethanol = 257 g

Cp = 2.4 j/g.°C

Chnage in temperature = ΔT = 49.1°C

Heat required = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = 257 g× 2.4 j/g.°C × 49.1 °C

Q = 30284.88 j

8 0
3 years ago
2.4 g of a solid is added to 91 g of water. What is the mass % concentration of the solution?
vladimir2022 [97]

Answer:

2.64%

Explanation:

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mass percent = (2.4 / 91) × 100

mass percent = 2.64% to 3sf

8 0
1 year ago
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