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tatiyna
3 years ago
14

what is the  concentration of a NaCl solution, in Molarity, if you add 59.76 g of NaCl into 270 mL of H2O

Chemistry
1 answer:
enot [183]3 years ago
7 0

Hey there!

Molar mass NaCl = 58.44 g/mol

Number of moles

n =  mass of solute / molar mass

n = 59.76 / 58.44

n = 1.0225 moles of NaCl

Volume in liters:

270 mL / 1000 => 0.27 L

Therefore:

M = number of moles / volume ( L )

M = 1.0225 / 0.27

= 3.78 M

Hope that helps!

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The relative volumes of chloroform and water that should be used is 9:10

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K_D = Concentration of solution in chloroform / Concentration of solution in water

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K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }

Since 90 mole is present in chloroform and 10 mole is present in water, Total mole of Caffeine present is 100

Now, we substitute our given values into the equation

10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}  \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10

Therefore, the relative volumes of chloroform and water that should be used is 9:10

Learn more; brainly.com/question/11060225

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2 years ago
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<h3>What is an outlier?</h3>

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