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DerKrebs [107]
2 years ago
6

Decomposition of hydrogen peroxide: 2H2O2 --> O2(g) + 2H2O(l) How many molecules of water are produced from the decomposition

of 3.4g of hydrogen peroxide, H2O2?
Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
8 0

Answer:

Explanation:

You have the equation. Now change the 3.4 g H2 to moles. moles = grams/molar mass

<em>3.4 g/2.016 = 1.686 moles.</em>

Now using the coefficients in the balanced equation, convert moles H2O2 to moles H2O.

1.686 moles H2 x (2 moles H2O/2 moles H2O2) = 1.686 x (2/2) = 1.686 x (1/1) = 1.686 moles H2O.

Now you know that 1 mole of water is composed of 6.022 x 10^23 molecules. So

1.686 moles H2O x (6.022 x 10^23 molecules H2O/1 mole H2O) = ?? molecules.

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8 0
3 years ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is 16.84 nm. What is the total wi
nadezda [96]

Answer:

u can just multiply 1

Explanation:

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3 0
1 year ago
An isotope has a half-life of 10 minutes. after 20 minutes, what percentage of the original nuclei remain?
Elena-2011 [213]
To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ  
   
where, t1/2 is half-life and λ is the decay constant.

t1/2 = 10 min = 0.693 / λ

Hence, λ = 0.693 / 10 min              -         (1)

Nt = Nο e∧(-λt)    
                
Nt = amount of atoms at t =t time
Nο= initial amount of atoms
t = time taken

by rearranging the equation,
Nt/Nο = e∧(-λt)                  -  (2)

From (1) and (2),

Nt/Nο = e∧(-(0.693 / 10 min) x 20 min) 
Nt/Nο = 0.2500

Percentage of remaining nuclei = (nuclei at t time / initial nuclei) x 100%
                                                     
= (Nt/Nο ) x 100%
                                                      = 0.2500 x 100%
                                                      = 25.00%

Hence, Percentage of remaining nuclei is 25.00%
6 0
2 years ago
What is the electron configuration for iodine
iogann1982 [59]

Hello!

To find electron configuration for Idoine we need to understand the following steps:

  1. Finding the Atom's Atomic Number (tells us the specific number of electrons)
  2. Determining the Charge of the Atom
  3. Understanding the orbitals (Set S [Contains 2], P [Contains 3, Holds 6], D [Contains 5, Holds 10], F [Contains 7, Holds 14], and there are some theoritical ones.) [Overall the sets go SPDFGHIK
  4. Understanding notations in configuartion. The notations display the number of electrons in the atom and set.

In this case, for Iodine. If we follow these rules we can see that the electron configuration is [Kr] 4d^10 5s^2 5p^5. We use Krytpon in front because that is the last full and stable noble gas before this particular element. Atoms are just trying to be stable so the goal is to achieve that full shell.

7 0
3 years ago
Guys please help me with this question!
damaskus [11]
A reducing agent is one which is oxidised in the reaction itself. When you take into account the oxidation numbers you will see that the Cl- ions are oxidised from an oxidation number of -1 to 0 in Cl2. Therefore Cl- ions are the reducing agent.
3 0
3 years ago
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