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3 years ago

What are all the factors of 54?

Mathematics

2 answers:

nekit [7.7K]3 years ago

8 0

Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54.

Step2247 [10]3 years ago

5 0

Answer:

1, 2, 3, 6, 9, 18, 27, 54 (answer choice D. for edge students)

Step-by-step explanation:

Factorization deals with listing out the highest multiples of the given number, it's really a matter of knowing your times tables, but informational search engines/websites works just fine as a substitution.

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Hunter-Best [27]

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3 years ago

Mrs Perry shares out 21 biscuits between

avanturin [10]

Answer:

Gemma gets 3 biscuits

Zak gets 18 biscuits

Step-by-step explanation:

1:6 = 1+6

= 7

1/7 * 21 = 3

6/7 * 21 = 18

4 0

3 years ago

Read 2 more answers

Después de 15 meses de haber prestado un capital al 5% de rédito, tengo que pagar de interés Q468.75. ¿Qué capital se ha prestad

Aleonysh [2.5K]

The capital borrowed, or the principal when the interest was Q468.75 is Q7500.

The principal P, amount borrowed, at a certain rate of interest R%, for a time of T years, giving an interest of I, can be calculated using the formula:

P = (I * 100)/(R * T).

In the question, we are asked to find the capital borrowed, that is, the principal, when the user pays Q468.75 after 15 months at 5% of income.

Thus, Interest (I) = Q468.75, rate of interest (R) = 5%, and time (T) = 15 months = 15/12 years = 1.25 years.

Thus, the principal P, can be calculated by substituting the values in the formula: P = (I * 100)/(R * T).

P = (468.75*100)/(5*1.25),

or, P = 46875/6.25,

or, P = 7500.

Thus, the capital borrowed, or the principal when the interest was Q468.75 is Q7500.

The provided question is in Spanish. The question in English is:

"After 15 months of having borrowed capital at 5% of income, I have to pay Q468.75 in interest. What capital has been borrowed?"

Learn more about Interest at

brainly.com/question/25793394

#SPJ1

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2 years ago

HELP I GIVE BIG BRAIN!!! see attachment

Evgesh-ka [11]

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2 years ago

Comparing Leaking Pool Problem

Blababa [14]

Answer:

Pool 1 leaks faster than pool 2.

Step-by-step explanation:

Rates of change

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

$\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h$

Pool 2:

$\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h$

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0

3 years ago