<span>The lithospheric plates float on top of the _______, which is a weak part of the mantle that flows slowly.
</span>
asthenosphere
Answer:
400 K
Explanation:
Charles's law states:
A determined volume of a gas is directly proportional to its temperature, while we have constant pressure.
V₁ / T₁ = V₂ / T₂
We replace data:
5 L / 100K = 20L / T₂
T₂ = 20L . 100K / 5 L
T₂ = 400 K
The volume was quadrupled, so the temperature did.
If we want T° at Celsius degree:
400 K - 273 = 127°C
This is true! Heterozygous would be Dd, and the dominant masks the recessive
<em>The cathode is Y</em>
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Further explanation</em></h3>
Electrolysis uses electrical energy to carry out redox reactions that are not spontaneous.
The ions in the solution flowing electrically will move towards to opposite charge of the electrode
The electrolysis material is an electrolyte which can be a solution or a melt.
In positive pole electrolysis cells - the anode is the site of the oxidation reaction, while the negative pole - the cathode is the reduction reaction site.
The result of the reaction in the anode is based on a substance that easily oxidized while the reaction in the cathode is based on a substance that easily reduced.
Electrons (electricity) enter an electrolysis cell through the negative pole (cathode)
The negative ion from the solution will move towards the positive electrode and release the electrons around the positive electrode (oxidation) and the electrons flow to the negative pole
Whereas around the negative electrode, there is electron binding and a reduction reaction occurs
So if we see the picture the cathode is Y
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Learn more</em></h3><h3><em>
reaction related to electrochemistry brainly.com/question/3461108</em></h3>
<h3><em>
Answer details </em></h3>
Grade: Senior High School
Subject: Chemistry
Chapter: Electrochemistry
Keywords: cathode, anode, oxidation, reduction, negative pole, electrode
Answer:
The rate law is [B]
Explanation:
In Trials 1 and 2, the concentration of B changes and A is the same so you can see how changes in B affect the rate. In this case, 0.300/0.150=2 and 7.11 x 10^-4 / 3.56 x 10^-4= 2. Since there 2^1=2, we can say that the reaction order of B is 1.
Similarly, if we look at trials 2 and 3, the concentration of B is constant, while A is changing. In this case, the rate has not changed at all with a change in concentration of A, so this means that A has 0 order.
Therefore, the rate law is just [B].
