Answer:
The new volume is 1.62 L
Explanation:
Boyle's law says:
"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." It is expressed mathematically as:
Pressure * Volume = constant
o P * V = k
Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. So this law indicates that the quotient between pressure and temperature is constant.
Gay-Lussac's law can be expressed mathematically as follows:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law.
Having an initial state 1 and a final state 2 it is possible to say that:
Standard temperature and pressure (STP) indicate pressure conditions P = 1 atm and temperature T = 0 ° C = 273 ° K. Then:
- P1= 1 atm
- V1= 1.2 L
- T1= 273 °K
- P2= 0.80 atm
- V2= ?
- T2= 21°C= 294 °K
Replacing:
Solving:
V2= 1.62 L
<u><em>The new volume is 1.62 L</em></u>
<u><em></em></u>
Answer:
1. NaCl
.
Explanation:
Hello there!
In this case, it is necessary to keep in mind that just ionic compounds are able to conduct electricity and therefore, the more ionic the compound is, the more electricity it conducts. In such a way, we may be able to predict how ionic these compounds are, considering that the electronegativity increases from bottom to top and from left to right.
1. NaCl: this is the most ionic compound since it is at the leftmost group and bonded with chlorine, so this is the most conductive one.
2. Mg(CIO3)2: Mg is bonded to O, not to Cl, which makes the compound ionic but not as ionic as NaCl.
3. NiCl: Ni is more electronegative than Na and Mg, so even when this is ionic, it is not as ionic as NaCl.
4. CaCl2: This is similar to NaCl but since Ca is in group 2A, it is more electronegative than Na, which makes CaCl2 conductive but not as much as NaCl.
Best regards!
Answer:
- The graphs that come with this question are in the picture attached.
- The answer is graph identified with the letter A.
Explanation:
The normal boiling point of water is 100°C. That is the temperature at which water boils when the atmospheric pressure is 1 atm, i.e. at sea level.
The liquids boil when its vapor pressure equals the atmospheric pressure; so the higher the atmospheric pressure the higher the boiling point, and the lower the atmospheric pressure the lower the boiling point.
Since, it is stated that the altitude of Denver, Colorado is 1,600 m, the atmosperic pressure (ther pressure exerted by the columnn of air above the place) is lower than 1 atm (atmospheric pressure at sea level).
Hence, water boiling point in Denver is lower than 100°C.
The graphs shown represent the temperature (T °C) as water is heated. Since when liquids boil their temperature remains constant during all the phase change, the flat portion of the graph represents the time during which the substance is boiling.
In the graph A, the flat portion is below 100°C; in the graph B, the flat portion is at 100 °C; in the graph C the flat part is above 100ªC, and, in graph D, there is not flat part. Then, the only graph that can illustrate water boiling in Denver, Colorado is the graph A.
Answer:
1.070MKCl
Explanation:
So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)
Since we do not have liters in this problem, we would need to convert milliliters to liters
<u>213 mL= 0.213 L</u>
We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>
Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.
M=n/L
M=0.228 mol/0.213L
M= 1.070MKCl
I know this was long, but I hope this helps (:
Explanation:
There are 6.022x1023 molecules in 1 mole of SO3 (Avogadro's number) so in 0.25 moles, there are (0.25)(6.022x1023) molecules in the 0.25 moles of SO3. or 1.506x1023 molecules per 0.25 moles of SO3.
There is one atom of sulfur in each molecule of SO3. So there are 1.506x1023 atoms of sulfur in 0.25 moles of SO3.
