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2 years ago

What are the difficulties encountered in precipitation titration

1 answer:

8 0

One difficulty encountered in precipitation titration is that it is hard to determine the exact end point of its reaction.

Precipitation titration is a titration in which a reaction occurs from the analyte and titrant to form an insoluble precipitate.

With the use of silver for the titrations, (argentometric) we are able to develop many precipitation reactions.

The precipitation titrimetry methods with the use of argentometry includes

• Mohr’s Method

• Fajan’s Method

• Volhard’s Method

Difficulties encountered in precipitation titration includes

Getting the exact end point is hard.

it is a very slow titration method.

it includes periods of filtration and cooling thereby reducing the reactions available for this type of titration.

See more on Precipitation: brainly.com/question/20628792

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What is the edge length of a 369-g iron cube?(The density of iron is 7.86 g/cm3, and the volume of a cube is equal to the edge l

Galina-37 [17]

Answer:

edge length = 3.61 cm

Explanation:

Givens

m = 369 gm

d = 7.86 gm / cm^3

v = ?

Formula

v = m / d

Solution

v = 369 / 7.86

v = 46.95 cm^3

============

That's not the answer. You must take the cube root of the volume

side = cube root (46.95)

side = 3.61 cm

6 0

3 years ago

7th grade science , please don’t get the answer from the internet :(

Liula [17]

Answer:

See the answer below

Explanation:

1. Organisms produce energy for cells by chemically breaking down and unlocking the energy locked-up within food materials in a process known as cellular respiration. The unlocked energy is then utilized for the cell's metabolic activities.

2. Cellular respiration can be aerobic or anaerobic.

Aerobic respiration involves the breakdown of carbohydrates in the presence of oxygen to yield energy in the form of ATP while carbon dioxide and water are produced as by-products.

$C_6H_1_2O_6 + 6O_2 --> 6CO_2 + 6H_2O + ATP$

Anaerobic respiration involves the breakdown of carbohydrates in the absence of oxygen to produce ATP and lactic acid as a by-product. The lactic acid is later oxidized to carbon dioxide and water to prevent it from building up.

$C_6H_1_2O_6 -> 2C_3H_6O_3 + ATP$

3. Photosynthesis and cellular respiration are both considered metabolic processes that take place in living organisms. However, photosynthesis is peculiar only to green plants and some algae while respiration is common to all living organisms. While photosynthesis is anabolic, that is, it involves the building up of materials; respiration is said to be catabolic because it involves the breaking down of materials.

During photosynthesis, inorganic products are utilized to produce carbohydrates for plants with oxygen gas released as a by-product according to the following equation:

$6CO_2 + 6H_2O --> C_6H_1_2O_6 + 6O_2$

During respiration, the food taken by living organisms is broken down to unlock the energy in it for metabolic activities according to the following equation:

$C_6H_1_2O_6 + 6O_2 --> 6CO_2 + 6H_2O + ATP$

7 0

3 years ago

a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the

butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

$\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}$

Given ,

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7 ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (21.7 + 273.15) K = 294.85 K

T₂ = (28.1 + 273.15) K = 301.25 K

Using above equation as:

$\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}$

$\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K }}{0.998\ atm}$

$n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol$

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0

4 years ago

In a compound, chemical energy is _______________ when bonds break.

Romashka-Z-Leto [24]

Answer:

In a compound, chemical energy is _____required__________ when bonds break.

6 0

3 years ago

If a 750 mL of a gas at a pressure of 100.7 kPa has a decrease of pressure to 99.8 kPa, what is the new volume? Show work

SVEN [57.7K]

Explanation:

P1V1 = P2V2

(100.7 kPa)(0.75 L) = (99.8 kPa)V2

V2 = (100.7 kPa)(0.75 L)/(99.8 kPa)

= 0.757 L

4 0

3 years ago