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asambeis [7]
3 years ago
7

If a 50 kg student is standing on the edge of a cliff. Find the student’s gravitational potential energy if the cliff is 80 m hi

gh.
Physics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

Student’s(50 kg) gravitational potential energy if the cliff is 80 m high = 39.2 kJ

Explanation:

   Potential energy is given by the expression, PE =mgh, m is the mass, g is the acceleration due to gravity value and h is the height.

 Here mass of student, m = 50 kilogram

           Height of cliff , h = 80 meter

           Acceleration due to gravity = 9.8m/s^2

 Potential energy, PE = 50 * 9.8 * 80 = 39200 J

                                    = 39.2 kJ

Student’s(50 kg) gravitational potential energy if the cliff is 80 m high = 39.2 kJ

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Answer:

Work done, W = 1.44 kJ

Explanation:

Given that,

Mass of boy, m = 74 kg

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Final speed of boy, v = 8.5 m/s

To find,

Non-conservative work was done on the boy.

Solution,

The work done by the non conservative forces is equal to the sum of total change in kinetic energy and total change in potential energy.

W=\dfrac{1}{2}m(v^2-u^2)+(0-mgh)

W=\dfrac{1}{2}m(v^2-u^2)-mgh

W=\dfrac{1}{2}\times 74\times (8.5^2-1.6^2)-74\times 9.8\times 1.56

W = 1447.21 Joules

or

W = 1.44 kJ

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3 years ago
21% of the atmosphere a:Nitrogen B:Oxygen C:CO^2 D:Argon
Vilka [71]
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4 years ago
A 2kg blob of putty moving at 4 m/s slams into a 6kg blob of putty at rest what is the speed of the to stick together blobs imme
andrew11 [14]
<h2>Answer</h2>

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<h2>Explanation</h2>

Given that:

<em>Mass of first blob = 2kg = m1</em>

<em>Velocity of blob = 4m/s = v1</em>

<em>Mass of second blob = 6kg = m2</em>

<em>Velocity of blob = 0m/s = v2</em>

<em />

To find:

<em>Final velocity = Vf</em>

<em />

<em>This question is of inelastic collision which is any collision between objects in which some energy is lost.</em>

<em />

<h3>Formula to be use:</h3><h2>(m1*v1) + (m2*V2) = Vf(m1 + m2)</h2>

(2*4) + (6*0) = Vf(2+6)

8 + 0 = Vf(8)

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3 years ago
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Answer:bottom left

Explanation:

8 0
3 years ago
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Answer:

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3 years ago
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