All categories

3 years ago

A flat coil of wire is placed in a uniform magnetic field that is in the y-direction.

Physics

1 answer:

Kitty [74]3 years ago

7 0

Answer:

The correct answer is c

Explanation:

Flow is defined by

Ф = B . A

bold letters indicate vectors.

The magnetic field is directed to the y axis, The area of the coil is represented by a vector normal to the plane of the coil, so to have a flux

i.i = j.j = k.k = 1

and the tori scalar products are zero

a) If the coil must be in the xy plane so that its normal vector is in the Z axis, so there is no flux

b) if the coil is in the plane yz the normal veto is in the x axis, so the flux is zero

C) If the coil is in XZ, the normal vector points in the y direction, usually the scalar product is one and there is a flux in this configuration

The correct answer is c

You might be interested in

Forecasting the time of, location, and magnitude of a seismic event does not prevent

Drupady [299]

<span>Forecasting the time of, location, and magnitude of a seismic event does not prevent
the event from happening, but it can help us reduce the destruction caused by
A) earthquakes.</span>

4 0

3 years ago

An airplane is traveling at 250 m/s in level flight. If the airplane is to make a change in direction, it must travel is a horiz

Nonamiya [84]

Answer:

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

Explanation:

We assume that airplane can be represented as a particle. The free body diagram of the vehicle is presented below as attachment, whose variables are:

$W$ - Weight of the airplane, measured in newtons.

$F$ - Lift, measured in newtons.

$\theta$ - Banking angle, measured in sexagesimal degrees.

The equations of equilibrium associated with the airplane are, respectively:

$\Sigma F_{r} = F\cdot \sin \theta = m\cdot \frac{v^{2}}{R}$ (Eq. 1)

$\Sigma F_{z} = F\cdot \cos \theta - W = 0$ (Eq. 2)

From (Eq. 2):

$F = \frac{W}{\cos \theta}$

In (Eq. 1):

$W\cdot \tan \theta = m\cdot \frac{v^{2}}{R}$

By using the definition of weight, we eliminate the mass of the airplane:

$g\cdot \tan \theta = \frac{v^{2}}{R}$

Where:

$g$ - Gravitational acceleration, measured in meters per square second.

$v$ - Speed, measured in meters per second.

$R$ - Radius of curvature, measured in meters.

Lastly, we clear the radius of curvature with the expression:

$R = \frac{v^{2}}{g\cdot \tan \theta}$

If we know that $v = 250\,\frac{m}{s}$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\theta = 15^{\circ}$ , the radius of curvature is:

$R = \frac{\left(250\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot \tan 15^{\circ}}$

$R = 23784.356\,m$

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

6 0

4 years ago

A radioactive sample has a count rate of 10,000 Bq. 24 days later the activity has fallen to 625 Bq. What is the half-life of th

joja [24]

Answer:

10000 Bq / 625 Pq = 16

Radioactivity has decreased by a factor of 16

2^4 = 16

So the sample has gone thru 4 half-lives

24 da / 4 = 6 da

6 da is the half-life

6 0

2 years ago

Choose the +x-direction to point to the right. • Object 1 has a mass 1.66 kg and is moving to the right at 11.2 m/s. • Object 2

egoroff_w [7]

Answer:

M = 49.4kgm/s (towards the left)

Explanation:

Momentum is the product of mass and velocity of an object

Momentum = mass * velocity

Momentum of Object 1 with mass 1.66 kg moving to the right at 11.2 m/s, is expressed as:

M1 = 1.66 * 11.2

M1 = 18.592kgm/s

Momentum of Object 2 with mass 6.59 kg moving to the left at 10.4 m/s is expressed as:

M2 = 6.59 * -10.4

M2 = -68.536kgm/s (negative since it is moving towards the left)

The total momentum will be the sum of momentum along the x-component as shown:

M = M1+M2

M = 18.592kgm/s--68.536kgm/s

M = -49.944kgm/s

M = 49.4kgm/s (towards the left)

5 0

3 years ago

If Mike does 25.5 J of work lifting a book 1.5 m onto a shelf what is the mass of the book in kilograms

Akimi4 [234]

Lifting the book means that the object gains gravitational potential energy. GPE=mass*gravitational field strength*height, ∴m=GPE/gh, m=25.5/10*1.5=1.7 kg

7 0

3 years ago