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Elena L [17]
3 years ago
9

An industrial engineer is designing a process to manufacture bullets. The mass of each bullet must be within 0.25% of 170.0 grai

ns. What range of bullet masses, in mg, will meet this tolerance? (1 gr = 64.79891 mg)
Physics
1 answer:
kondaur [170]3 years ago
7 0

Answer:

The range is 11015.81468 ± 27.53953675 mg.

Explanation:

The mass of each bullet must be within 0.25% of 170.0 grains.

We need to calculate the range of bullet masses

Mass of grains is given by,

\dfrac{0.25}{100}\times170.0=0.425

1\ g grain = 64.79891\ mg

0.425\ grains = 64.79891\times0.425

0.425\ grains = 27.53953675\ mg

170.0\ grains =\dfrac{27.5395367\times170.0}{0.425}

170.0\ grains =11015.81468\ mg

Hence, The range of bullet masses are 11015.81468 ± 27.53953675 mg.

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We must give full information on this problem, as well as the question that needs to be resolved.

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The solution of the equations and the free body diagram can be seen in the attached picture.

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