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tino4ka555 [31]
3 years ago
13

Questlon 6 of 10

Physics
1 answer:
victus00 [196]3 years ago
7 0

Answer:

The two poles closest to each other are opposite magnetic poles

Explanation:

Just took the test

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Machines A, B, and C do the same amount of work, but they each take a different amount of time. Machine A takes more time as com
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So power is considered as the rate of doing work. Base on the problem given, my analysis is that the machine who finish the work faster is machine C. Therefore, in order to finish the same amount of work in a short period of time you are going to expend the most power. My answer is Machine C. 
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Which of these forces help protons and neutrons to stay at the center of the Atom
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Strong nuclear force
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What would be the resulting charge of carbon (C) after this element loses four electrons?
Sladkaya [172]

Answer:

Carbon will become positively charged.

The charge of Carbon will be +4.

Explanation:

The charge of Carbon will be +4.

In the periodic table, elements that give out  or lose electrons during electrochemical combinations are called electropositive elements. If carbon loses electrons during the chemical combination, Carbon will become positively charged, with a valency equal to the number of electrons that it lost.

This will make carbon have a charge of +4

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3 years ago
Fossil fuels like gasoline or coal are examples of
disa [49]

Answer:

Nonrenewable Resources

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3 years ago
The mean time between collisions for electrons in room temperature copper is 2.5 x 10-14 s. What is the electron current in a 2
Darya [45]

Answer:

1.87 A

Explanation:

τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s

d = diameter of copper wire = 2 mm = 2 x 10⁻³ m

Area of cross-section of copper wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (2 x 10⁻³)²

A = 3.14 x 10⁻⁶ m²

E = magnitude of electric field = 0.01 V/m

e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

m = mass of electron = 9.1 x 10⁻³¹ kg

n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³

i = magnitude of current

magnitude of current is given as

i = \frac{Ane^{2}\tau E}{m}

i = \frac{(3.14\times 10^{-6})(8.47\times 10^{28})(1.6\times 10^{-19})^{2}(2.5\times 10^{-14}) (0.01)}{(9.1\times 10^{-31})}

i  = 1.87 A

4 0
3 years ago
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