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3 years ago

A mechanic pushes perpendicularly on the end of a 0.15m wrench. If the

Physics

1 answer:

kumpel [21]3 years ago

4 0

Answer:

τ = 34.5 N.m

Explanation:

The force applied by the mechanic is 230 N.

Thus, F = 230 N

Now, this force is applied in a counterclockwise manner while pushing perpendicularly at the end of the 0.15m long wrench.

Thus, r = 0.15 m

Formula for the torque in this case is;

τ = Fr sin θ

θ = 90° since mechanic pushed perpendicularly.

Thus;

τ = 230 × 0.15 × sin 90

τ = 34.5 N.m

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A house is 54.0 ft long and 48 ft wide, and has 8.0-ft-high ceilings. What is the volume of the interior of the house in cubic m

pshichka [43]

Explanation:

Length of house, l = 54 ft = 16.45 m

Breadth of house, b = 48 ft = 14.63 m

Height of house, h = 8 ft = 2.43 m

We need to find the volume of the interior of the house. The house is in the form of cuboid. The volume of cuboid is given by :

$V=l\times b\times h$

$V=16.45\ m\times 14.63\ m\times 2.43\ m$

$V=584.81\ m^3$

Since, $1\ m^3=1000000\ cm^3$

or the volume of the interior of the house, $V=5.84\times 10^8\ cm^3$

Hence, this is the required solution.

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3 years ago

What is an equilibrant

professor190 [17]

The question seems to be what is an equilibrant force.

The answer is "an added force that produces equilibrium.

Here you have more insight:

<span>an object that has no net force acting on it? This object indeed is in equilibrium but the object is not the equilibran force.

the reaction force in an action-reaction pair of forces?

the reaction force is not an equilibrant force. The reaction force exists always but equilibrium is only possible if the net force is cero.

an added force that produces equilibrium? this is the right answer.</span>

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4 years ago

Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. the sheet has parallel faces and the glass h

mestny [16]

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4 years ago

A new mechanic foolishly connects an ammeter with 0.1 Ω resistance directly across a 12-V car battery with internal resistance o

NemiM [27]

Answer:

The power dissipated by the meter is 1188W

Explanation:

Here we have a circuit constituted with a power source and two resistors in series, we can calculate the power dissipated by the meter using the following formula:

$P=I^2R_m$