Motaion would be it have a good day
Answer:
I₄ / Io = 0.388 = 38.8%
Explanation:
For this exercise we will analyze the effect of having two depolarizers with an annulus between them, this is described by Malus's law
I = Io cos² θ
where tea is the angle between the two polarizers.
For this case we must apply this law to each pair of polarizers.
The light that reaches the first polarizer is non-polarized light, therefore only the light that has polarization is transmitted in the direction of the depolarizer, which is horizontal.
I₁ = I₀ / 2
this intnesidad reaches the second polarizer that has an angle of 23º with respect to the first polarizer
I₂ = I₁ cos² 23
I₂ = I₀ / 2 0.847
This light reaches the third polarizer, which has an angle of 42º with respect to the first polarized one.
Let's find the angle with respect to the 2nd polarizer
θ = 42- 23
θ = 19º
we apply the law of Malus
I₃ = I₂2 cos 19
I₃ = I₀ 0.847 / 2 0.9455
I₃ = Io 0.4
This intensity of light reaches the fourth polarizer, with an angle of 14º with respect to the 3polarizer
I₄ = Io 0.4 cos 14
I₄ = Io 0.4 0.970
I₄ = Io 0.388
to give this result as a percentage
I₄ / Io = 0.388 = 38.8%
when we find the distance we will add all the blocks so
distance = 6+6+4
distance = 14blocks
when we find the displacement we will add and minus too
As you can read he goes to the south 6 and to north 6 so he leave that place and back to the place again so the displacement is 0. and again he goes to the west 4 blocks so the displacement = <em><u>4blocks</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>west</u></em>
Answer:
The elastic potential energy is zero.
The net force acting on the spring is zero.
Explanation:
The equilibrium position of a spring is the position that the spring has when its neither compressed nor stretched - it is also called natural length of the spring.
Let's now analyze the different statements:
The spring constant is zero. --> false. The spring constant is never zero.
The elastic potential energy is at a maximum --> false. The elastic potential energy of a spring is given by
where k is the spring constant and x the displacement. Therefore, the elastic potential energy is maximum when x, the displacement, is maximum.
The elastic potential energy is zero. --> true. As we saw from the equation above, the elastic potential energy is zero when the displacement is zero (at the equilibrium position).
The displacement of the spring is at a maxi
num --> false, for what we said above
The net force acting on the spring is zero. --> true, as the spring is neither compressed nor stretched
Answer:
-5 m/s²
Explanation:
Acceleration = change in velocity / change in time
a = (v − v₀) / (t − t₀)
a = (-0.4 m/s − 0.6 m/s) / 0.2 s
a = -5 m/s²
The ball decelerates at a rate of -5 m/s².