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stiv31 [10]
3 years ago
15

Mendeleev noticed that if he organized the elements by atomic weight certain patterns emerged. for instance, elements in the sam

e group (family) appeared to have the same

Physics
2 answers:
Anvisha [2.4K]3 years ago
7 0

Answer:

Elements it the same group have the same properties as listed below.

Explanation:

1) The same number of electrons in their valence shell

2) The same chemical properties

3) Atomic size

4) Ionic size

5) Ionization potential

6) Electropositivity increases

7) Electronegativity decreases

8) Electron gain enthalpy

DENIUS [597]3 years ago
4 0
Properties. Each family has it's own properties, features, and even things like color, malleability, or conductivity.

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A 10 kg farm wagon is sitting at the top of a hill that makes a 370 angle with the horizontal when the brake suddenly fails. The
yanalaym [24]

Answer:

F = 1475.75 N      

Explanation:

Given:-

- The mass of the wagon m = 10 kg

- The slope angle θ = 37°

- The initial velocity of wagon at top of hill, vi = 0 m/s

- The amount of distance it plows into haystack, s2 = 2.0 m

-The wagon rolls down the slope for distance, s1 = 50 m

Find:-

Determine The force the haystack exerts on the wagon?

Solution:-

- First we must note that the wagon rolls down the slope with a constant acceleration due to gravity ( g ) component acting down the slope. The acceleration ( a ) of the wagon can be given as:

                       a = g*sin ( θ ).

- Since, the acceleration of the cart is constant we can apply third kinematic equation of motion with initial velocity at top of hill vi = 0 m/s and the velocity " v1 " right before it plows into the haystack at the bottom of hill after traveling a distance of s1 = 50 meters.

                       v1^2 = vi^2 + 2*a*s1  

                       v1^2 = 0 + 2*g*sin ( θ )*s1  

                       v1^2 = 2*9.81*sin ( 37 )*50    

                       v1 = √590.381

                       v1 = 24.30 m/s

- The constant force exerted by the haystack ( F ) as the wagon plows the haystack with a velocity "v1" by a distance of s2 and comes to, final velocity vf = 0, a stop.

Apply principle of work-done energy:

- Where, work is done on the wagon by haystack for W = F*s2.

                    W = Δ K.E        

                    W = 0.5*m* ( vf^2 - v1^2 )

                    F*s2 = 0.5*m*( v1 )^2

                    F = 0.5*m*( v1 )^2 / s2

                    F = 0.5*10*590.30 / 2    

                    F = 1475.75 N          

8 0
3 years ago
A piece of hot copper of mass 4.00 kg has it's temperature decrease by 36.90 ºC when it is placed in a body of water of unknown
Ainat [17]

Answer:

1.48 kg

Explanation:

mass of copper = 4 kg

Decrease in temperature of copper = 36.9°C

increase in temperature of water = 9.20°C

Let the mass of water is m.

Specific heat of water = 4181 J/Kg°C

Specific heat of copper = 385 J/kg°C

According to the principle of caloriemetery

Heat lost by copper = heat gained by water

mass of copper x specific heat of copper x decrease in temperature = mass of water x specific heat of water x increase in temperature

4 x 385 x 36.9 = m x 4181 x 9.20

56826 = 38465.2 m

m = 1.48 kg

Thus, the mas of water is 1.48 kg.

mas of water

5 0
4 years ago
Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of
Ganezh [65]

Answer:

B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are m_A and m_B respectively.

As masses are equal, so m_A=m_B\cdots(i).

Similarly, let the radii of the planets A and B are r_A and r_B respectively.

As radii are equal, so r_A=r_B\cdots(ii).

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A, w_A= \frac {Gm_Am}{r_A^2}

my weight of planet B, w_B=\frac {Gm_Bm}{r_B^2}

By using equations (i) and (ii),

w_B=\frac {Gm_Am}{r_A^2}=w_A.

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (B) is correct.

4 0
3 years ago
What is gravitational acceleration​
Thepotemich [5.8K]

Answer:

gravitational acceleration is the acceleration of an object in free fall within a vacuum (and thus without experiencing drag). This is the steady gain in speed caused exclusively by the force of gravitational attraction.

6 0
3 years ago
Read 2 more answers
Which is an example of a solution?
vladimir1956 [14]

Answer:

C

Explanation:

plato

6 0
3 years ago
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