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3 years ago

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Mendeleev noticed that if he organized the elements by atomic weight certain patterns emerged. for instance, elements in the sam

e group (family) appeared to have the same

2 answers:

Anvisha [2.4K]3 years ago

7 0

Answer:

Elements it the same group have the same properties as listed below.

Explanation:

1) The same number of electrons in their valence shell

2) The same chemical properties

3) Atomic size

4) Ionic size

5) Ionization potential

6) Electropositivity increases

7) Electronegativity decreases

8) Electron gain enthalpy

DENIUS [597]3 years ago

4 0

Properties. Each family has it's own properties, features, and even things like color, malleability, or conductivity.

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A hurricane is a huge storm that forms over warm ocean waters. Many hurricanes enter the Gulf of Mexico and move in a northweste

labwork [276]

Answer:

536.448m/s or 20miles/hr

Explanation:

Speed is defined as the distance travelled by a body or an object in a specified time.

Speed = Distance/Time

If a hurricane travels a distance of 20 miles in 1 hour.

Distance travelled = 20miles

Time taken = 1hour

Speed = 20miles/1hour

Speed = 20miles/hr

Since 1mile = 1609.344m

20miles = 20×1609.344

20miles = 32186.88m

1hour = 60seconds

Expressing the speed in m/s

Speed = 32186.88m/60s

Speed = 536.448m/s

5 0

2 years ago

Photosynthesis occurs in a plant cell's

Fynjy0 [20]

Answer:

Photosynthesis occurs in the organelle, chloroplast .

Cellular respiration occurs in a plants or animals mitochondria.

Explanation:

Hope this helps! :)

5 0

3 years ago

What is instantaneous acceleration?

KengaRu [80]

Answer:

how fast the car goes

Explanation:

3 0

3 years ago

Read 2 more answers

A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr

fgiga [73]

Answer:

<em>The balloon is 66.62 m high</em>

Explanation:

<u>Combined Motion </u>

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

$\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}$

The values are

$\displaystyle y_o=15\ m$

$\displaystyle v_o=14\ m/s$

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

$\displaystyle y=0$

$\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0$

Multiplying by 2

$\displaystyle 2y_o+2v_ot-gt^2=0$

Clearing the coefficient of $t^2$

$\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0$

Plugging in the given values, we reach to a second-degree equation

$\displaystyle t^2-2.857t-3.061=0$

The equation has two roots, but we only keep the positive root

$\displaystyle \boxed {t=3.69\ s}$

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

$\displaystyle Y_r=15+V_r.t$

$\displaystyle Y_r=15+14\times3.69$

$\displaystyle \boxed{Y_r=66.62\ m}$

3 0

2 years ago

Captain John Stapp is often referred to as the "fastest man on Earth." In the late 1940s and early 1950s, Stapp ran the U.S. Air

valentina_108 [34]

Answer:

The sled needed a distance of 92.22 m and a time of 1.40 s to stop.

Explanation:

The relationship between velocities and time is described by this equation: $v_f=v_0+a*t$ , where $v_f$ is the final velocity, $v_0$ is the initial velocity, $a$ the acceleration, and $t$ is the time during such acceleration is applied.

Solving the equation for the time, and applying to the case: $t=\frac{v_f-v_0}{a}=\frac{0\frac{m}{s}-282\frac{m}{s} }{-201\frac{m}{s^2} }=1.40s$ , where $v_f=0\frac{m}{s}$ because the sled is totally stopped, $v_0=282\frac{m}{s}$ is the velocity of the sled before braking and, $a=-201\frac{m}{s^2}$ is negative because the deceleration applied by the brakes.

In the other hand, the equation that describes the distance in term of velocities and acceleration: $x_f-x_0=v_0*t+\frac{1}{2}*a*t^2$ , where $x_f-x_0$ is the distance traveled, $v_0$ is the initial velocity, $t$ the time of the process and, $a$ is the acceleration of the process.

Then for this case the relationship becomes: $x_f-x_0=282\frac{m}{s} *1.40s+\frac{1}{2}(-201\frac{m}{s})*(1.40s)^2=94.22m$ .

<u>Note that the acceleration is negative because is a braking process.</u>

4 0

3 years ago

Read 2 more answers