This is the definition of specific heat capacity. 1000J of heat are required to raise the temperature of 1kg of the compound by 1 degree. Therefore a 1000J have been added to the block.
Answer:
<em>If you have any questions, comment</em>
Explanation:
a. time of flight =(2usinθ)/(g/6)
= 12usinθ/g
= (12x25xsin(30))/g
<h3>
= 15.306 seconds
</h3>
b. Range = u2sin(2θ)/(g/6)
= 6u2sin(2θ)/g
= (6x252xsin(60)) /9.8
= 331.387 metres
c. Range on earth = Range on moon/6 = 55.23 metres
On moon it travels 331.387 - 55.23 = 276.155 metres more than on earth
Answer:
the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine.
Explanation:
Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. The device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever.
Answer:
t = 66.7 s
Explanation:
Given that,
Speed of a hare, v = 15 m/s
Speed of a turbocharged tortoise, v' = 3 m/s
The hare in a 250 meter race
Let the Hare takes time t. It can be calculated as follows :
![t=\dfrac{250}{15}=16.67\ s](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B250%7D%7B15%7D%3D16.67%5C%20s)
Let a turbocharged tortoise takes t'. It can be calulated as follows :
![t'=\dfrac{250}{3}= 83.33\ s](https://tex.z-dn.net/?f=t%27%3D%5Cdfrac%7B250%7D%7B3%7D%3D%2083.33%5C%20s)
To tie the race, required time is given by :
![\Delta t = t'-t\\\\=83.33-16.67\\\\=66.66\ s\\\\\approx 66.7\ s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20t%27-t%5C%5C%5C%5C%3D83.33-16.67%5C%5C%5C%5C%3D66.66%5C%20s%5C%5C%5C%5C%5Capprox%2066.7%5C%20s)
Hence, the correct option is (b) i.e. 66.7 seconds.
Answer:
a) t = 0.528 s
b) D = 1.62 m
Explanation:
given,
speed of the baseball = 3.75 m/s
angle made with the horizontal = 35°
height of the roof edge = 2.5 m
using equation of motion
![s = ut +\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=s%20%3D%20ut%20%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
![2.5 = vsin\theta \ t +\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=2.5%20%3D%20vsin%5Ctheta%20%5C%20t%20%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
![2.5 = 3.75\ sin35^0 \ t +\dfrac{1}{2}\times 9.8 t^2](https://tex.z-dn.net/?f=2.5%20%3D%203.75%5C%20sin35%5E0%20%5C%20t%20%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.8%20t%5E2)
4.9 t² + 2.15 t - 2.5 = 0
on solving the above equation
t = 0.528 s
b) D = v cos θ × t
D = 3.75 × cos 35° ×0.528
D = 1.62 m