Someone who snorts and stop breathing during sleep may be suffering from: a. Catoplexy b. Narcolepsy c. Sleep Apnea d. Insomnia

Physics

1 answer:

klio [65]3 years ago

6 0

Answer:

C. Sleep Apnea

Explanation:

Sleep Apnea is when someone who snores and stops breathing while sleeping

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Tarzan (75 kg) swings from 4 metres high on a vine down to ground level and catches Jane (50 kg). How fast are they moving after

Kruka [31]

Try this solution (if it is possible, check it in other sources):

1. for m_Tarzan=75kg., initial_height=4m., end_height=0 m. and g=10 N/kg. Energy is:

$E=m_{Tarzan}*(H_{initial}-H_{end})*g=75*4*10=3000(J).$

2. The same value of Energy is applied for m_Tarzan+Jane=75+50=125 kg.:

$E=\frac{m_{Tarzan+Jane}* Speed^2}{2}; \ => \ Speed=\sqrt{ \frac{2*E}{m_{Tarzan+Jane}}};$

3. According to the formula of the Speed:

Speed=sqrt(6000/125)=sqrt(48)=4sqrt(3)≈4*1.71=6.84 (m/s)

Answer: 6.84 (m. per sec.)

5 0

3 years ago

HELP PLEASE!<br> write the equation for calculating relative velocity in one dimensional.

RoseWind [281]

Anwer:

Key Equations

Position Vector: `n r (t) = (t)^j+y

Total acceleration: `n a = `n aC

+ `n aT

Position Vector in frame S is the position Vector in frame S` plus the vector from the origin of S to the origin of S`: `n rPS = `n rPS`

+ `n rS`S

Relative velocity equation connecting two references frame: `n vPS = `n vPS`

+ `n vS`S

6 0

3 years ago

15 Points , Physics HW, can someone please show me step by step how to calculate percent difference for this problem. My numbers

timofeeve [1]

The percent difference between two numbers $x$ and $y$ is given by

$\dfrac{|y-x|}x \times 100\%$

The absolute value is there because we only care about the absolute percent difference, and not taking into account whether we go from $x$ to $y$ or vice versa. If we remove them, we have two possible interpretations of percent difference.

For example, the (absolute) percent difference between 3 and 6 is

$\dfrac{|6-3|}3 \times 100\% = 100\%$

In other words, we add 100% of 3 to 3 to end up with 6. This is the same as the percent difference going from 3 to 6. On the other hand, the percent difference going from 6 to 3 is

$\dfrac{3-6}3\times100\%=-50\%$

which is to say, we take away 50% of 6 away from 6 to end up with 3.

"Make comparisons to object measurements" tells us that the differences should be computed relative to "measurements for object". In other words, take $x$ from the left column and $y$ from the right column.

$\dfrac{|7.1-7.3|}{7.1} \times 100\% \approx 2.82\%$