Answer:
57.885.8 kg weight of the container
Explanation:
The volume of the balloon * density of water = buoyant force of balloon
volume of a sphere = 4/3 pi r^3
= 4/3 pi * (1.5)^3 = 14.14 m^3 <===balloon volume
Now, find the buoyant force on the container ALONE ....
5.8 * 2.6 * 2.8 * 1027 = 43 364 kg <===== buoyant force
Now add the buoyant force of the balloon to find the weight
43 364 + 14.14 * 1027 = 57885.8 kg
The collapsed answer of Penchalreddy Badepalli is correct. The composition of two reflections via two mirror making an angle \alpha is equivalent to a single rotation by an angle 2\alpha, hence 2 * 60 deg = 120 deg. And turns is independent of the absolute orientation of the two mirrors in space and/or the direction of incidence of the incoming ray.
One could use elementary geometry to prove this (if you presume the direction of incidence is irrelevant imagine hitting the first mirror at 90 deg, then going retro right back along the normal to the first mirror, and follow the directions).
Explanation:
Given that,
Average power of sun 
We need to calculate the intensity of light at Earth's position
Using formula of intensity

Where, I = intensity
P = power
Put the value into the formula


So, The intensity is 1347.616 W/m².
(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective
Using formula for fully reflective

Put the value into the formula


(B). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective
Using formula for fully absorptive



Hence, This is the required solution.
Answer:
a force that attracts matter to the earth
Explanation:
depends on where you are the gravity can be different in space there is no gravity on Earth there is , that's why when you jump you come back down
The correct answer is "None of the above; all of these statements are valid." All the statements namely, it depends on the particle's charge, it depends on the strength of the external magnetic field, it depends on the particle's velocity, and it acts at right angles to the direction of the particle's motion are all valid. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.