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3 years ago

How is it possible for two objects to have the same momentum but different velocities give an example

1 answer:

4 0

Momentum is
p = mv, where m is the mass and v is the speed.
So, if two objects have the same momentum but different speeds, the must have different masses as well.
v1/v2 = m2/m1
The example is a car and a truck. Car has the mass 1000 kg and velocity 100 m/s, and truck has the mass 5000 kg and velocity 20 m/s. Use the formula above to determine is it true that they have the same momentum:
(100 m/s) / (20 m/s) = (5000 kg) / (1000 kg)
5 = 5
So, the example is correct.
Hope this helps! Good luck!

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An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction

DiKsa [7]

Refer to the diagram shown below.

The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²

After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
= m(u/2)²
= (1/4)mu²
= (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer: 1/2

5 0

4 years ago

Read 2 more answers

Which type of foot PPE must you wear if electrical shock is ever a possibility with your job?

ira [324]

The appropriate PPE(personal protective equipment) to be worn for foot protection against electric shock is boots retrofitted with rubber soles. Rubber does not conduct electricity and so will safeguard against electric shocks.

Other personal protective equipment used in a lab or industry can include safety glasses, rubber gloves, protective clothing and masks and respirators. PPE goes hand in hand with personal behaviour, personal grooming and housekeeping.

7 0

3 years ago

The distance and displacement of a object in motion can be the same (true or false)

Rasek [7]

Aswer:

False, the values of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.

Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.

<u>xXCherryCakeXx</u>.

4 0

3 years ago

Ignoring air resistance and the little friction from the plastic tube, the magnet was a freely-falling object in each trial. If

horsena [70]

Answer:

emf will also be 10 times less as compared to when it has fallen $40 \mathrm{m}$

Explanation:

We know, from faraday's law-

$e m f=-N \frac{\Delta \Phi}{\Delta T}$

and $\Phi=B . A$

So, as the height increases the velocity with which it will cross the ring will also increase. $(v=\sqrt{2 g h})$

Given

$\mathrm{V} 1(\text { Speed at } 40 \mathrm{m})=2 \mathrm{x} \mathrm{V} 2(\text { speed at } 10 \mathrm{m})$

$\sqrt{2 g h_{2}}=2 \times \sqrt{2 g h_{1}}=28.28 \mathrm{m} / \mathrm{s}$

Now, from $40 \mathrm{cm}$

$V_{3}=\sqrt{2 g h_{3}}=\sqrt{2 \times 10 \times 0.4}=2.82 \mathrm{m} / \mathrm{s}$

From equation a and b we see that velocity when dropped from $40 \mathrm{m}$ is 10 times greater when height is 40 $\mathrm{cm}$ so, emf will also be 10 times less as compared to when it has fallen $40 \mathrm{m}$

4 0

3 years ago

A net force acting on an object will always cause a change in the object's _________.

Nataly [62]

cause a change in the object's velocity

3 0

3 years ago