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3 years ago

A credit report maintains negative financial information for how many years?

Mathematics

1 answer:

Dimas [21]3 years ago

8 0

I believe the answer is B

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You are designing a ramp where the horizontal distance is twice the vertical rise. what will be the ramp angle to the nearest te

ankoles [38]

Use the definition of tangent

or inv tangent (arctan or atan)

tan(theta) = opposite side/ adjacent side

the vertical rise would be the opposite side, the horozontal distance would be the adjacent side

let rise = y
let distance= x
x=2y

so tan(theta) = y/2y
tan(theta) = 1/2

theta = atan(1/2)

grab a handy dandy calculator, unless you know this conversion off the top of your head

7 0

3 years ago

On your first draw, what is the probability of drawing a red card, without looking, from a shuffled deck containing 6 red cards,

Elis [28]

First divide 6/(6+6+8) =0.3
Then multiple it by 100 to get the probability percentage 30%

5 0

2 years ago

What's 2/8 divided by 5/16 simplified in fraction form?

irga5000 [103]

$\frac{2}{8} \div \frac{5}{16} = \frac{2}{8} \times\frac{16}{5} = \frac{1}{4} \times\frac{16}{5} = \frac{4}{5} = 0.8$

3 0

3 years ago

Read 2 more answers

Ten experts rated a newly developed chocolate chip cookie on a scale of 1 to 50. Their ratings were: 34, 35, 41, 28, 26, 29, 32,

miskamm [114]

The mean deviation of the ratings is 4.12

Explanation

The ratings of the ten experts are: 34, 35, 41, 28, 26, 29, 32, 36, 38 and 40

So, the mean of all ratings $=\frac{34+35+41+28+26+29+32+36+38+40}{10}= \frac{339}{10}=33.9$

The formula for Mean deviation $= \sum \frac{|x_{i}- \mu|}{N}$ , where $x_{i}$ is the given data from $i=1$ to $i=10$ , $\mu$ is the mean of the data and $N$ is the total number of data. So.....

$|x_{1}-\mu |= |34-33.9|=0.1\\ |x_{2}-\mu|=|35-33.9|=1.1\\ |x_{3}-\mu |=|41-33.9|=7.1\\ |x_{4}-\mu |=|28-33.9|=5.9\\ |x_{5}-\mu |=|26-33.9|=7.9\\ |x_{6}-\mu |=|29-33.9|=4.9\\|x_{7}-\mu |=|32-33.9|=1.9\\ |x_{8}-\mu |=|36-33.9|=2.1\\ |x_{9}-\mu |=|38-33.9|=4.1\\ |x_{10}-\mu |=|40-33.9|=6.1$

So, the Mean deviation $=\sum \frac{|x_{i}-\mu |}{N}=\frac{0.1+1.1+7.1+5.9+7.9+4.9+1.9+2.1+4.1+6.1}{10} = \frac{41.2}{10}=4.12$

4 0

3 years ago

What is the inter-quartile range of the given data set? a. 2 b. 3 c. 6

babunello [35]

Answer:

b. 3

Step-by-step explanation:

20-17=3

5 0

3 years ago