Answer:
Density is the ratio of the mass of an object to its volume. Density is an intensive property, meaning that it does not depend on the amount of material present in the sample. ... Since a cubic centimeter is equal to a milliliter, density units can also be expressed as g/mL.
Explanation:
Answer:
Mass = 10.0 g
Explanation:
Given data:
Molarity = 1.50 M
Volume = 210 mL ( 0.21 L)
Grams of CH₃OH = ?
Solution:
Number of mole = molarity × volume
Number of mole = 1.50 M × 0.21 L
Number of mole = 0.315 mol
Mass of CH₃OH:
Mass = Number of moles × molar mass
Mass = 0.315 mol × 32.04 g/mol
Mass = 10.0 g
Answer:
Oxidation Number of Phosphorous = + 6
Explanation:
According to Rules of Assigning Oxidation States;
i) The Oxidation State of Hydrogen atom in a compound is assigned as +1 except for Hydrides i.e. NaH and MgH₂ where it is assigned with -1.
ii) The Oxidation State of Oxygen in a compound is assigned as -2 except for Peroxides where it is given -1 and OF₂ where it is assigned with +1 respectively.
Oxidation State of P in H₂P₃O₁₀;
As over all molecule is neutral we can write it as,
H₂P₃O₁₀ = 0
Putting oxidation number of H and O,
(+1)₂ + P₃ + (-2)₁₀ = 0
(+2) + P₃ + (-20) = 0
+ 2 + (P)3 -20 = 0
(P)3 = + 20 - 2
(P)3 = + 18
P = + 18 ÷ 3
P = + 6
Answer:
Yeah chemical change occurs when you fry an egg since the whites harden and change shape in a way. Mass is conserved since it doesn't change.
This uses the concept of freezing point depression. When faced with this issue, we use the following equation:
ΔT = i·Kf·m
which translates in english to:
Change in freezing point = vant hoff factor * molal freezing point depression constant * molality of solution
Because the freezing point depression is a colligative property, it does not depend on the identity of the molecules, just the number of them.
Now, we know that molality will be constant, and Kf will be constant, so our only unknown is "i", or the van't hoff factor.
The van't hoff factor is the number of atoms that dissociate from each individual molecule. The higher the van't hoff factor, the more depressed the freezing point will be.
NaCl will dissociate into Na+ and Cl-, so it has i = 2
CaCl2 will dissociate into Ca2+ and 2 Cl-, so it has i = 3
AlBr3 will dissociate into Al3+ and 3 Br-, so it has i = 4
Therefore, AlBr3 will lower the freezing point of water the most.
