A standard drink of beer is 12 ounces
Answer:
We'll have 82 moles ZnO and 41 moles S
Explanation:
Step 1: data given
Number of moles Zinc (Zn) = 82 moles
Number of moles sulfur oxide (SO2) = 42 moles
Step 2: The balanced equation
2Zn + SO2 → 2ZnO + S
Step 3: Calculate the limiting reactant
For 2 moles Zinc we need 1 mol sulfur oxide to produce 2 moles zinc oxide and 1 mol sulfur
Zinc is the limiting reactant. It will completely be consume (82 moles). Sulfur oxide is in excess. There will react 82/2 = 41 moles
There will remain 42-41 = 1 mol SO2
Step 4: Calculate moles of products
For 2 moles Zinc we need 1 mol sulfur oxide to produce 2 moles zinc oxide and 1 mol sulfur
For 82 moles Zinc we'll have 82 moles of Zinc Oxide (ZnO)
For 82 moles Zinc we'll have 82/2 = 41 moles of sulfur
We'll have 82 moles ZnO and 41 moles S
The number of micrograms of contaminant each person will receive is 5,742.64 ug.
<h3>
Number of micrograms of contaminant per person</h3>
The number of micrograms of contaminant each person will receive is calculated as follows;
Amount of contaminant (mg) = (1.01 x 10⁻⁴ mg/mL) x 2.28 x 10⁴ L
Amount of contaminant (mg) = 2.3028 mg.L/mL
Amount of contaminant (mg) = (2.3028 mg.L/mL) x (1000 mL/L) = 2,302.8 mg
Amount of contaminant (ug) = 2,302.8 mg x 1000 ug/mg = 2,302,800 ug
<h3>Amount of contaminant per person (ug/person) </h3>
= (2,302,800 ug) / (401 persons)
= 5,742.64 ug per person
Learn more about micrograms of contaminant here: brainly.com/question/14522199
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