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marshall27 [118]
4 years ago
10

Which is larger 18% or 2/11?

Mathematics
2 answers:
Cloud [144]4 years ago
8 0

2/11 is larger.

Explanation :

Because if you cover it to decimal,

18% will be 0,18 only

but

2/11 will be 0,188888-

which means it can be 0,19 if 2 decimal behind coma and of course 0,19 is larger dan 0,18

try devide 2 with 11 .

yarga [219]4 years ago
6 0
I believe they have the same value.
If you divide 2/11, your answer will be .181818..
If you round it off it will be .18
To convert to percent, Move the decimal point 2 places to the right and add the percent sign. .18 is 18%
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3 years ago
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An angle measures 51.4° less than the measure of its complementary angle. What is the measure of each angle?
kap26 [50]

Answer:

70.7 deg, 19.3 deg

Step-by-step explanation:

The sum of the measures of complementary angles is 90 deg.

One angle measures x.

The other angles measures 51.4 deg less than x, or x - 51.4.

The sum of their measures equals 90.

x + x - 51.4 = 90

2x - 51.4 = 90

2x = 141.4

x = 70.7

x - 51.4 = 70.7 - 51.4 = 19.3

Answer: 70.7 deg, 19.3 deg

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​ Quadrilateral ABCD ​ is inscribed in this circle. What is the measure of angle B? Enter your answer in the box. m∠B= ° A quadr
Over [174]

Answer:

m∠B = 157°

Step-by-step explanation:

Cyclic quadrilateral is the quadrilateral whose vertices lie on the edge of the circle

In the cyclic quadrilateral each two opposite angles are supplementary (the sum of their measures is 180°)

∵ Quadrilateral ABCD is inscribed in a circle

- That means its four vertices lie on the edge of the circle

∴ ABCD is a cyclic quadrilateral

<em>Each two opposite angles in the cyclic quadrilateral are supplementary (The sum of their measures is 180°)</em>

∵ ∠B and ∠D are opposite angles in the quadrilateral ABCD

∴ m∠B + m∠D = 180° ⇒ opposite ∠s in a cyclic quadrilateral

∵ m∠B = (6x + 19)°

∵ m∠D = x°

- Substitute them in the rule above

∴ (6x + 19) + x = 180

- Add the like terms in the left hand side

∴ (6x + x) + 19 = 180

∴ 7x + 19 = 180

- Subtract 19 from both sides

∴ 7x = 161

- Divide both sides by 7

∴ x = 23

<em>Substitute the value of x in the expression of the measure of ∠B to find its measure</em>

∵ m∠B = 6(23) + 19

∴ m∠B = 138 + 19

∴ m∠B = 157°

5 0
4 years ago
A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L
Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider \Delta ABC as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}

From the given data, L=15\:ft=AC, y=9\:ft=AB and x=BC

Substituting the values,  

\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}

\therefore 81+x^{2}=225

\therefore x^{2}=225-81

\therefore x^{2}=144

\therefore \sqrt{x^{2}}=\sqrt{144}

\therefore x=\pm 12

Since length can never be negative, so x= 12.

Now to calculate \dfrac{dy}{dt} again consider following equation,  

\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}

Differentiate both sides of the equation with respect to t,  

\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)

Applying sum rule of derivative,

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)

Applying power rule of derivative,  

2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0

Simplifying,  

y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0

Substituting the values,  

9\dfrac{dy}{dt}+12\times1.5=0

9\dfrac{dy}{dt}+18=0

Subtracting both sides by 18,

9\dfrac{dy}{dt}=-18

Dividing both sides by 9,

\dfrac{dy}{dt}= - 2

Here, negative indicates that the ladder is sliding in downward direction.  

\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}

7 0
3 years ago
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