Answer:
81
Step-by-step explanation:
A composite number has factor more than just one and itself.
Factors of 81=
1, 3, 9, 27, 81
Answer:
2 solutions
Step-by-step explanation:
I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...
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To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:
3x(x -4) +5 -x -(2x -7) = 0
3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses
3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms
3(x -1)(x -4) = 0 . . . . . . . . . . . . . . . factor
The values of x that make these factors zero are x=1 and x=4. These are the solutions to the equation. There are two solutions.
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<em>Alternate method</em>
Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...
d = b^2 -4ac . . . . where a, b, c are the coefficients in the form ax^2+bx+c
d = (-15)^2 -4(3)(12) = 225 -144 = 81
This positive value means the equation has 2 real solutions.
Answer:
13i/5
Step-by-step explanation:
25z^2+140=-29 subtract 140 from both sides
25z^2=-169 now square root both sides.
=
a negative root forms i
5z=13i
z=13i/5
Minus 3y both sides
2y-6=-20
add 6 to both sids
2y=-14
divide 2
y=-7
Answer:
D) -4 (with imaginary roots ±2i)
Step-by-step explanation:
Since you cannot take the square root of a negative number to produce a real result, the only option that has two imaginary roots is D) -4, where the two imaginary roots are 2i and -2i.