Answer:
Heat flow is the movement of heat.
Explanation:
Heat flows in solids by conduction, which occurs when two objects in contact with each other transfer heat between them. That happens because the molecules hit each other, and the faster moving molecules in the hot object spread that energy into the cooler object
Credit to, https://study.com/academy/lesson/heat-flow-in-solids-fluids.html
Answer:
Explanation:
Frictional force acting on the box = mg cos 25 x μ where μ is coefficient of friction
= 2.4 x 9.8 x cos 25 x .51 = 10.87 N
Weight of the box acting along the incline = mg sin 25 = 9.94 N
Net force = 10.87 - 9.94 = .93 N . It will create a deceleration of .93 / 2.4
= .3875 m /s² in the box.
v² = u² - 2 a s
v = 0 , a = .3875 , s = 5.4 m
= = u² - 2 x .3875 x 5.4
u = 2.045 m /s
The activity occurring at an axon terminal involves the following labelled 1 - 6:
- synaptic vesicles
- synapse
- motor end plates (neurotransmitter receptor)
- calcium channel
- neurotransmitters
- axon
The transmission of nerve impulses between neurons, muscles cells or glands is known as nervous transmissions.
Axons are long slender projections of neurons which are responsible for nervous transmission.
Neurons use both electrochemical signals and chemicals known as neurotransmitters to transmit impulses from one neuron to the next.
The junction between two neurons or an effector cell is known as a synapse.
Neurotransmitters are packaged into synaptic vesicles at the axon end. When electrical signal reaches the end of the axon, influx of calcium ions through the calcium channel cause the the synaptic vessels to fuse with the presynaptic membrane and then release their contents into the synaptic cleft or space.
The neurotransmitters released then bind to the motor end plate resulting in another impulse transmission along the second neuron or an action by effector cells.
Learn more at: brainly.com/question/783627
Answer:
![0.0035\ \text{m}](https://tex.z-dn.net/?f=0.0035%5C%20%5Ctext%7Bm%7D)
Explanation:
y = Distance from the center point
d = Separation between slits = 0.3 mm
D = Distance between slit and screen = 1.5 m
= Wavelength = 700 nm
m = Order = 1
We have the relation
![d\dfrac{y}{D}=m\lambda\\\Rightarrow y=\dfrac{Dm\lambda}{d}\\\Rightarrow y=\dfrac{1.5\times 1\times 700\times 10^{-9}}{0.3\times 10^{-3}}\\\Rightarrow y=0.0035\ \text{m}](https://tex.z-dn.net/?f=d%5Cdfrac%7By%7D%7BD%7D%3Dm%5Clambda%5C%5C%5CRightarrow%20y%3D%5Cdfrac%7BDm%5Clambda%7D%7Bd%7D%5C%5C%5CRightarrow%20y%3D%5Cdfrac%7B1.5%5Ctimes%201%5Ctimes%20700%5Ctimes%2010%5E%7B-9%7D%7D%7B0.3%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5CRightarrow%20y%3D0.0035%5C%20%5Ctext%7Bm%7D)
The distance from the screen at which the first bright fringe beyond the center fringe appear is
.