We calculate as follows:
d = 0.025 m
<span>Δx = 0.31 m
</span>
<span>W = pΔV = p(πd²)(Δx/4) </span>
<span>W = 2.4x10⁵(3.14x0.025²)(0.31/4) =36.5 J
</span>
<span>F = W / Δx = 36.5 / 0.31 = 117.8 N
</span>
Hope this answers the question. Have a nice day.
For this problem, we combine the concepts learned in physics and in calculus. The velocity, by definition, is the total distance travelled per time elapsed. It can also be expressed in Δx/Δt, This is also a definition in calculus where dx/dt is equal to velocity. Therefore, to solve the velocity, differentiate the equation in terms of t.
x = 2 cos(10t)
dx/dt = 2*(-sin(10t))*(10)
dx/dt = -20sin (10t)
We are asked to find the velocity at 0.40 seconds. Thus, we substitute t = 0.40 to the equation
dx/dt = -20sin(10*0.4)
dx/dt = v = -1.395 m/s
Therefore, the velocity at t=0.04 seconds is -1.395 m/s. The negative sign connotes that the direction of the motion is south or to the left based on the sign convention.
The resultant of the two forces, vertical ground reaction force and frictional force is 1907.8784 N.
<h3>What is triangle law of vectors?</h3>
When two vectors are represented by magnitude and direction, then its resultant is given by the closing side of the triangle.
Given the vertical ground reaction force N = 2000N and horizontal frictional force F = 600N, then the resultant will be
R = √[(2000)² + (600)²]
R = 1907.8784 N
Thus the resultant force is 1907.8784 N
Learn more about triangle law of vectors.
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Mg = 6.2 x 9.81 = 60.822
This is also normal force.
Coefficient of friction times normal force is the force due to friction:
60.822 x 0.24 = 14.6N
F = MA so F(your force) - F(friction) = 6.2 x 0.5
= 3.1
Your answer is 3.1+ 14.6
I hope this is correct though I might be wrong.
Answer:
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Explanation: