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Naya [18.7K]
2 years ago
9

An empty graduated cylinder weighs 82.450

Physics
1 answer:
avanturin [10]2 years ago
4 0
Because when you think about it it has to start off as a solid 
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4) You have a 10 ohm resistor connected in series with an ammeter. The voltage applied to the whole circuit is 1.2 volts. At the
GuDViN [60]

Answer:

0.6 Ω

Explanation:

As shown in the diagram below,

Since the resistance and the ammeter are connected in series,

(i) The same amount of current flows through them.

(ii) The sum of their individual individual voltage is equal to the total voltage of the circuit.

Applying ohm's law,

V = IR................ Equation 1

Where V = Voltage across the ammeter, I = current flowing through the ammeter, R = resistance of the ammeter.

make R the subject of the equation

R = V/I............... Equation 2

Given: V = 1.2-0.9 = 0.3 V, I = 0.5 A.

Substitute into equation 2

R = 0.3/0.5

R = 0.6 Ω

3 0
2 years ago
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In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of t
muminat
<h2><em><u>⇒</u></em>Answer:</h2>

In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.600 m and the acceleration achieved from this position is 1.25 times the acceleration due to gravity, g . How far can they jump? State your assumptions. (Increased range can be achieved by swinging the arms in the direction of the jump.)

Step-by-Step Solution:

Solution 35PE

This question discusses about the increased range. So, we shall assume that the angle of jumping will be  as the horizontal range is maximum at this angle.

Step 1 of 3<

/p>

The legs have an extension of 0.600 m in the crouch position.

So,  m

The person is at rest initially, so the initial velocity will be zero.

The acceleration is  m/s2

Acceleration  m/s2

Let the final velocity be .

Step 2 of 3<

/p>

Substitute the above given values in the kinematic equation  ,

m/s

Therefore, the final velocity or jumping speed is  m/s

Explanation:

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3 years ago
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An enemy sub is approaching a us submarine at 25.0 km/hr that is waiting in ambush. the us submarine needs to know the exact pos
Illusion [34]
Speed of the Enemy sub .....> <span> 25.0 km/hr which is (25/3.6) m/s = 6.94 m/s

We use the expression Speed = Distance/ time to find the distance

D = Speed*Time = 6.94 m/s * 3.5  = 24.305 m

The enemy sub will be 24.305 m closer 
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