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Naya [18.7K]
3 years ago
9

An empty graduated cylinder weighs 82.450

Physics
1 answer:
avanturin [10]3 years ago
4 0
Because when you think about it it has to start off as a solid 
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Explain the following situation using ONE CONCEPT, you must use language and concepts learned during the term:
asambeis [7]
The girl on the right thinks that being on the moon changes your mass, but this is inaccurate. Your mass stays the same, regardless of where you are, but your acceleration (weight) changes if you go to the moon.
4 0
3 years ago
A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the spee
dimulka [17.4K]
We can take as positive direction the direction of the train, and as negative direction the direction of the girl. The speed of the train relative to the girl will be given by the difference between the two velocities:
v' = v_t - v_g
which means
v'=75 m/s - (-10 m/s)=85 m/s
5 0
3 years ago
Read 2 more answers
As material from the outer envelope of the larger star builds up on the surface of the white dwarf, its temperature and density
stepan [7]

Answer:

Hydrogen will undergo nuclear fusion ,

Explanation:

here, it is being explained:-

The first thing that will inevitably arise would be that nuclear fusion would arise with hydrogen.

When fuel from the larger star's outer shell piles up on the white dwarf's surface, the temperature and density continuously increase as a result of which hydrogen will undergo nuclear fusion.

7 0
4 years ago
A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8
mylen [45]

Answer:

f = 2.6 \times 10^{-13}

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

N = \frac{m}{29} \times 6.02 \times 10^{23}

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

N_e = m(6.02 \times 10^{29})

now diameter of the ball is 7.0 mm

density of the ball = 8900 kg/m^3

now we have

m = (\frac{4}{3}\pi r^3)(8900)

m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)

m = 1.6 gram

now we have

N_e = 9.63 \times 10^{23}

now the charge on the copper ball is 40 nC

so the number of electrons removed

Q = ne

40 \times 10^{-9} = n(1.6 \times 10^{-19}

n = 2.5 \times 10^{11}

so the fraction of number of electrons removed is given as

f = \frac{n}{N_e}

f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}

f = 2.6 \times 10^{-13}

7 0
4 years ago
A 20-Kg child is on a swing attached to 3.0 m-long chains. The child swings back and forth, swinging out to a 60-degree angle. (
kvv77 [185]

Answer:

 v = 29.4 m / s

Explanation:

For this exercise we can use the conservation of mechanical energy

Lowest starting point.

          Em₀ = K = ½ m v²

final point. Higher

          Em_{f} = U = m g h

Let's use trigonometry to lock her up

          cos 60 = y / L

          y = L cos 60

Height is the initial length minus the length at the maximum angle

           h = L - L cos 60

           h = L (1- cos 60)

energy is conserved

         Em₀ = Em_{f}

          ½ m v² = mgL (1 - cos 60)

         v = 2g L (1- cos 60)

 

let's calculate

          v² = 2 9.8 3.0 (1- cos 60)

          v = 29.4 m / s

6 0
3 years ago
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