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goldenfox [79]
3 years ago
15

Work out the area of the triangle :) Show working out plz:)

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0
The formula for triangle area is b•h/ 1/2. so you would do 12•5=60. then divide that by 2 to get 30
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Is (1, 1) a solution to this system of equations?<br><br>11x+3y=18<br>4x+y=5
Mumz [18]

system of equations (1,1)

put value of these x and y in equations

(x , y) = ( 1,1)

so this solution not satisfied equation 1

11( 1)  + 3 (1)  = 18

so 11 + 3 =  18

   15   = 18 ( Left side not equal to right side )

  (1,1) is not solution for 11x+ 3y=18

2.     4x+y = 5

put values (1,1)

4(1)   + (1)    =  5

 5    =   5   {  left side =  right side )

so (1,1) is solution for 4x +y=5

8 0
3 years ago
Solve this problem and give the total cost
Jlenok [28]
F(h)= 20 +25h

next plug in the hours but first you need to take the minutes and transfer them to hours 

120 minutes = 2 hours

so you plug in 20 + 25(2)

that equals 70

therefor your answers are

f(h)= 20 +25h
and
$70
5 0
3 years ago
7. Find the volume of a square pyramid with a base length of 9 cm and a height of 4 cm.
Helga [31]

Answer:

Step-by-step explanation:

humba shea de mora 3end

4 0
3 years ago
Read 2 more answers
Write an equation in slope intercept form for this line (4,7) slope of -3/2
Vikki [24]

Answer:

y=-3/2x+13

Step-by-step explanation:

7=-3/2(4)+b

7=-6+b

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8 0
4 years ago
3r²-6-3r=0 i have to use quadratic formula but i dont get how to imput it
yKpoI14uk [10]

Answer:

r = 2

r = -1

Step-by-step explanation:

So first, we need to get this is order of: ax^2 + bx + c

3r^2 - 6 - 3r

3^2 - 3r - 6

the formula is: -b ± √b^2 -4ac/2a

"ax^2 + bx + c" = "3^2 - 3r - 6"

a = 3

b = -3

c = -6

-b ± √b^2 -4ac/2a

-(-3) ± √(-3)^2 -4(3)(-6)/2(3)

3 ± √9 + (-12)(-6)/6

3 ± √9 + (72)/6

3 ± √9 + 72/6

3 ± √81/6

3 ± 9/6

3 - 9/6

-6/6

-1 = r

3 + 9/6

12/6

2 = r

Formula down below --

                                      |

                                     V

4 0
3 years ago
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