Answer:
Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.
The answer & explanation for this question is given in the attachment below.
The sum of two irrational numbers, in some cases Will be irrational. However, if the rational parts of the numbers have a 0 sum (cancel each other out), the sum will be rational.
To answer this question we need to use subtraction.
we need to make the denominators the same.
In order to make them the same we need to find the least common multiple, of 8 and 5.
The least common multiple(the smallest shared value of the two numbers) is 40.
Next we divide our old denominator 5 by 40, which gives us 8, we multiply 8 by the numerator 2, which gives us 16. So now we have 16/20. We have to do the same to the other side. 8÷40 = 5. 5 x 3 = 15. Now we have 15/20.
Now we have a brand new equation, 16/40 - 15/40. The answer is 1/40.
In a fraction the answer is 1/40, so Karen rides her bike further.
In decimal form the answer is 0.025.
I hope this helps!
making x the subject
substitute into second equation
by solving, y=5
substitute into first equation
by solving, x=-3
Therefore the ordered pair is (-3,5)
