Interphase isn't part of mitosis because the cell doesn't divide in interphase.
Answer:
The relationship between photosynthesis and cellular respiration is such that the products of one system are the reactants of the other.
Explanation:
For example, the output of photosynthesis is the input of glucose production or cellular respiration. The output of glucose production is the input of photosynthesis. Photosynthesis involves the use of energy from sunlight, water, and carbon dioxide to produce glucose and oxygen. Cellular respiration uses glucose and oxygen to produce carbon dioxide and water. To emphasize this point, even more, the equation for photosynthesis is the opposite of cellular respiration.
If the tyre blows out then stop
Answer:
Atmosphere
Explanation:
carbon dioxide is naturally released into the atmosphere by the decay and flatulance of animals. But you extract fossil fuels from the ground and burn them. The burning of fossil fuels is called combustion.
Answer:
1/16
Explanation:
- scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
- ebony (e) is an autosomal mutation recessive to e+ (wild type).
The two genes are independent because they are located on different chromosomes.
<h3>
<u>Parental generation:</u></h3>
True breeding scalloped female wild type for ebony (<em>Xsd Xsd e+e+</em>) mates with a true breeding male mutant only for ebony (<em>Xsd+ Y ee</em>).
The female only produces <em>Xsd e+</em> gametes. The male produces <em>Xsd+ e</em> or <em>Y e</em> gametes.<u> Therefore, the F1 females will have the genotype </u><u><em>Xsd Xsd+ e e+ </em></u><u>and the F1 males will have the genotype </u><u><em>Xsd Y e e+.</em></u>
If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a<em> Xsd Xsd e e</em> genotype and appear in a 1/16 proportion.