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Andre45 [30]
3 years ago
12

What is the perimeter of this rectangle?

Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0
I think A. but I'm not a 100% sure
Inga [223]3 years ago
4 0

Answer:

The perimeter of the rectangle is given by

P=2(x_2-x_1)+2(y_2-y_1)

A is the correct option.

Step-by-step explanation:

Distance formula of two points is given by

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Using the distance formula,

Length of the rectangle is given by

l=\sqrt{(x_2-x_1)^2+(y_1-y_1)^2

l=\sqrt{(x_2-x_1)^2

l=(x_2-x_1)

Width of the rectangle is given by

w=\sqrt{(x_2-x_2)^2+(y_2-y_1)^2

w=\sqrt{(y_2-y_1)^2

w=(y_2-y_1)

Hence, the perimeter of the rectangle is given by

P=2l+2w\\\\P=2(x_2-x_1)+2(y_2-y_1)

A is the correct option.

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What is the solution of -8/2y-8=5/y+4-7y+8/y^2-16
Mnenie [13.5K]
<h2>Answer:</h2>

The solution of the given equation is:

                         y=6

<h2>Step-by-step explanation:</h2>

The expression is given by:

\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}

Now on solving for the given equation

\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}

since,

a^2-b^2=(a-b)(a+b)\\\\so,\\\\y^2-16=y^2-4^2\\\\i.e.\\\\y^2-16=(y-4)(y+4)

Hence, we get:

\dfrac{-4}{y-4}=\dfrac{5\times (y-4)-(7y+8)}{(y+4)(y-4)}\\\\i.e.\\\\\dfrac{-4}{y-4}=\dfrac{5y-20-7y-8}{(y-4)(y+4)}

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(y-4)(-4y+16)-(-2y-28)(y-4)=0\\\\i.e.\\\\(y-4)(-4y-16+2y+28)=0\\\\i.e.\\\\(y-4)(-2y+12)=0\\\\i.e.

y-4=0\ or\ -2y+12=0\\\\i.e.\\\\y=4\ or\ 2y=12\\\\i.e.\\\\y=4\ or\ y=6

but y≠ 4

since, the denominator of the term in the left side of the given equality and the second term in the right side of the given equality will be zero and hence, the expression will be not defined.

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7 0
4 years ago
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