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Vsevolod [243]
3 years ago
14

If 4x-1=X, Find 30x a) 10 b) 40 C) 12 d)11 How do you solve this?

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

(a)

Step-by-step explanation:

Given

4x - 1 = x ( subtract x from both sides )

3x - 1 = 0 ( add 1 to both sides )

3x = 1 ( multiply both sides by 10 )

30x = 10 → (a)

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What is the sum of the first seven terms of the geometric series where a1 = 10 and r = −2?
matrenka [14]
Sum_{7} = 10 *  \frac{1- (-2^{7}) }{1 - (-2)} =  10*  \frac{1+128}{1+2} = 10*  \frac{129}{3} =   10 * 43 = 430
4 0
3 years ago
A 20-pack of Dr. Pepper cost $5.50 and a 6-pack cost $1.50. Which is the better deal?​
Irina-Kira [14]

Answer:

Step-by-step explanation:

20-pack of Dr. Pepper cost $5.50 . As per this deal

  Cost of one pack = 5.5/20 = $ 0.275

a 6-pack cost $1.50.As per this deal

  Cost of one pack = 1.50/6 = $ 0.25

A 6-pack cost $1.50 is the better deal.

5 0
3 years ago
State if the two triangles are congruent. If they are, state how you know.
Gwar [14]

Answer:

The triangles can be congruent.

Step-by-step explanation:

They are congruent if proven by SSS: 2 sides are clearly stated that they are congruent due to the marks they have.

The last side can be congruent if the diagonals are congruent in length by proving.

They can also be congeuent due to SAS because there is gonna be alternate interior angles due to the transversal.

4 0
3 years ago
Find the value of x.<br> A<br> 28<br> 20<br> B<br> 9x – 8<br> С
natulia [17]

Answer:

The question is incorrect. please provide a diagram.

4 0
3 years ago
A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0
3 years ago
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