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2 years ago

If 4x-1=X, Find 30x a) 10 b) 40 C) 12 d)11 How do you solve this?

Mathematics

1 answer:

cestrela7 [59]2 years ago

3 0

Answer:

(a)

Step-by-step explanation:

Given

4x - 1 = x ( subtract x from both sides )

3x - 1 = 0 ( add 1 to both sides )

3x = 1 ( multiply both sides by 10 )

30x = 10 → (a)

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1. Which of the following coordinates for p will make line mn perpendicular to line op in the diagram below?

TiliK225 [7]

1. (3,2)....because when finding the slope, we find the the slope of mn and the slope of op are negative reciprocals.

2. y = 5x - 7.....slope here is 5....perpendicular line has a negative reciprocal slope...so the slope has to be -1/5

y= mx + b
slope(m) = -1/5
(-10,3)...x = -10 and y = 3
now we sub and find b, the y int
3 = -1/5(-10) + b
3 = 2 + b
3 - 2= b
1 = b
so ur perpendicular equation is : y = -1/5x + 1

5 0

2 years ago

I need step by step explanation and answer please

fredd [130]

Answer:

Step-by-step explanation:

Trigonometric identities:

$\sin^{2} (x) + { \cos}^{2} (x) = 1 \\ {\cos}^{2} (x) = 1 - { \sin}^{2} (x) \\ { \sin }^{2} x = 1 - {\cos}^{2} (x) \:$

Replace into the equation

$\frac{ \sqrt{1 - \cos^{2} (x) } }{ \sin(x) } + \frac{ \sqrt{1 - \sin^{2}(x) } }{ \cos(x) } \\ \\ = \frac{ \sqrt{ \sin^{2}(x) } }{ \sin(x) } + \frac{ \sqrt{ \cos^{2}(x) } }{ \cos(x) }$

Remove roots and simply

$= \frac{ \sin(x) }{ \sin(x) } + \frac{ \cos(x) }{ \cos(x) } \\ \\ = 1 + 1 \\ = 2$

7 0

2 years ago

Mhanifa please help! Find the length of the missing side in the following examples. round answers to the nearest tenth,if necess

GaryK [48]

Answer:

Use Pythagorean to solve these. Assume the missing side is x.

$x = \sqrt{7^2 -5^2} = \sqrt{24} = 4.9 m$

$x = \sqrt{10^2+15^2} = \sqrt{325} = 18.0 cm$

$x = \sqrt{25^2-8^2} = \sqrt{561} = 23.7 cm$

4 0

2 years ago

Determine whether or not the two equations below have the same solution. In two or more complete sentences, explain your rationa

Artist 52 [7]

Answer:

Yes, they have the same solution.

Step-by-step explanation:

The steps in solving a two-step equation are to simplify by using

The inverse of addition or subtraction and then
The inverse of multiplication or division

Equation 1

$\dfrac{2}{3}x + \dfrac{3}{4} = 8$

(a) Inverse of addition

$\begin{array}{rcl}\dfrac{2}{3}x + \dfrac{3}{4} - \dfrac{3}{4}& = & 8 - \dfrac{3}{4}\\\\\dfrac{2}{3}x & = & \dfrac{29}{4}\\\end{array}$

(b) Inverse of multiplication

$\begin{array}{rcl}\left (\dfrac{2x}{3}\right ) \left (\dfrac{3}{2}\right ) & = & \left (\dfrac{29}{4}\right ) \left ( \dfrac{3}{2} \right ) \\\\x & = & \dfrac{87}{8}\\\end{array}$

Equation 2

8x = 87

(a) Inverse of multiplication

$\begin{array}{rcl}\dfrac{8x}{8} & = & \dfrac{87}{8}\\\\x & = & \dfrac{87}{8}\\\end{array}$

The two equations have the same solution.

For the first equation, I used the inverse of addition and then the inverse of multiplication to get the value of x.

The second equation needed only the inverse of multiplication.

Both solutions were the same.

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=a%28n%29%3D3%2F2%28-2%29x%5E%7Bn-1%7D" id="TexFormula1" title="a(n)=3/2(-2)x^{n-1}" alt="a(n)=

hjlf

Answer:

i have no idea

Step-by-step explanation:

3 0

1 year ago