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Vera_Pavlovna [14]
3 years ago
15

2. Adelia holds a shiny steel spoon with its back (convex surface) facing her eyes at a distance

Physics
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:

(a) The convex mirror image, is always upright at all positions, while images formed by concave mirrors are always inverted when the object distance from the mirror is more than the mirrors focal length.

(b) An upright image is not seen for object at a distance from a concave mirror further than the focal length of the mirror, which is the spoon in the question

Therefore, the location of her eyes of approximately, 30 cm,  from the mirror is more than the mirror's focal length

Explanation:

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A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge
navik [9.2K]

The solution would be like this for this specific problem:

<span>
F=−</span>k∗x∗<span>q∗</span>Q<span>/(</span>+)<span>F−≈</span><span><span><span>k∗x∗<span>q∗</span>Q</span><span>/R3</span></span>[(</span>1−<span><span>3/2</span><span><span>*x2</span><span>/R3</span></span>]
</span><span>F=−</span><span><span>k∗x∗<span>q∗/</span>Q</span><span>R<span>3
</span></span></span><span>F=</span><span>ma
</span>−<span><span><span><span>k∗<span>q∗</span>Q</span><span>/R3</span></span>*</span>x</span>=<span>ma
</span>−k∗x=m∗<span>a
a</span>==<span><span><span>ω2</span>x
</span>ω</span><span>=(</span>k/<span>m<span>)<span><span>1/</span><span>2

</span></span></span></span>ω<span>=(</span><span>kqQ</span>/<span><span>R3</span><span>)<span><span>1/</span>2

</span></span></span>

<span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

5 0
3 years ago
Would this be 2N because 6 and 4 cancel out? Or no because 4 plus two is six and that cancels everything out to 0
soldier1979 [14.2K]

Answer: It would be 0

Explanation: Because like you said it would cancel each other out because if you are going 6N to the right and then you go 6N to the left you are actually not moving at all  

5 0
2 years ago
Can anyone please help meee!!!​
Neko [114]

Answer:

The centripetal acceleration is given by  

a = v 2 r = 10 2 25 = 4   m s − 2

Using Newton's Second Law, the centripetal force acting is  

F = m a = 900 ⋅ 4 =3600 N

Explanation:

5 0
3 years ago
How much energy must be transferred out of the system as heat q to lower its temperature to 0∘c? express your answer numerically
serg [7]

Answer:

Incomplete question:

Refer to the temperature versus time graph when answering the questions in Parts C through F. A system consists of 250 of water. The system, originally at = 21.0 , is placed in a freezer, where energy is removed from it in the form of heat at a constant rate. The figure shows how the temperature of the system takes to drop to, after which the water freezes. Once the freezing is complete, the temperature of the resulting ice continues to drop, reaching temperature after an hour. The following specific heat and latent heat values for water may be helpful.

specific heat of ice (at ) = 2.10 J/g K

latent heat of fusion (ice to water phase change at ) = 333.7 J/g

specific heat of water (at ) = 4.186 J/g K

latent heat of vaporization (water to steam phase change at ) = 2256 J/g

specific heat of steam (at ) = 2.01 J/g K

Answers:

Qtotal = 237775 J

Explanation:

To solve this exercise it is necessary to know that if the system is a single phase in which there is a temperature change or if it is a phase change at a single temperature. In the first case, the following formula would be used to calculate the amount of heat:

Q₁ = mCpΔT

Here

m is the mass = 250 g

Cp is the specific heat of ice = 2.1 J/g K

ΔT = 21 - 0 = 21°C = 294 K

In this case the amount of energy is

Q₁ = 250*2.1*294 = 154350 J

In the second case, where there is a phase change at a single temperature, the amount of heat is:

Q₂ = mLf

Here

Lf = latent heat of fusion (ice to water phase change) = 333.7 J/g

Substituting:

Q₂ = 250*333.7 = 83425 J

The total heat is:

Qtotal = 154350+83425=237775 J

7 0
3 years ago
If the sun is a medium sized star, why does it look bigger than others?
nata0808 [166]

Answer:

The sun looks bigger than other stars because it is closer to the Earth, distance makes it look larger

5 0
3 years ago
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