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Elanso [62]
3 years ago
12

The equilibrium reaction for calcium sulfate is shown here. What is the effect on the equilibrium reaction if calcium nitrate is

added to the solution?
A) The reaction would shift to the left and calcium sulfate would dissolve more readily.
B) The reaction would shift to the right and calcium sulfate would dissolve more readily.
C) The reaction would shift to the left and calcium sulfate would precipitate out of solution.
D) The reaction would shift to the right and calcium sulfate would precipitate out of solution.
Physics
2 answers:
natta225 [31]3 years ago
8 0

Answer:

a

Explanation:

Katarina [22]3 years ago
7 0

Answer:

The answer is C for those on USA Testprep.

Explanation:

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The speed of the ball moving is

v = 3.94 \times 10 {}^{ - 25}m/s

what is momentum?

The momentum p of a classical object of mass m and velocity v is given by pclassical =mv.

For photons with wavelength λ,this equation does not hold.Instead, the momentum of the Photon is given by p Photon = h/λ

where,h is the planck's constant.

The momentum of the red Photon is

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h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)

λ = 700 \times 10 {}^{ - 9} m(photons \: wavelength)

p \: photons =  \frac{6.626 \times 10 {}^{ - 34}kgm {}  ^{2}/s }{700 \times 10 {}^{ - 9}m  }

= 9.47 \times 10 {}^{ - 28}kgm /s

since,the Photon and the ping-pong ball have the same momentum,we have

pball = pphotons =  \frac{6.626 \times 10 {}^{ - 34}kgm/s  }{700 \times 10 {}^{ - 9} }

pball = mv,m = 2.40 \times 10 {}^{ - 3}kg

v = 3.94 \times 10 {}^{ - 25} m/s

Therefore, if the red photon and the ping-pong ball have the same momentum, the ping-pong ball must have a speed of approximately

v = 3.94 \times 10 {}^{ - 25}m/s

learn more about momentum of photon from here: brainly.com/question/28197406

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