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meriva
3 years ago
12

A positron undergoes a displacement ∆r= 2i -3j+6k, ending with the position vector r= 3j-4k, in meters. what was the positron's

initial position​
Physics
1 answer:
Margaret [11]3 years ago
3 0

\Delta{r}=2i-3j+6k \\r_f = 3j-4k \\\Delta{r}=r_f-r_0\Longrightarrow2i-3j+6k=3j-4k-r_0 \\r_0=2i-3j+6k+3j-4k=\boxed{2i+6j+10k}

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3 years ago
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