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3 years ago

If you are exposed to potentially infectious material via a sharps injury, what should you do immediately?

Engineering

1 answer:

Sergio039 [100]3 years ago

4 0

The correct answer is "immediately flood the area with water and clean the wound."

Further Explanation:

If someone is exposed to a potentially infectious material with a sharps item such a needle, they need to wash the area with clean water immediately. It must be a steady flow of water to get out any potential infectious material.

After flushing the injury with water, you will then wash the area or exposed skin with soap, if at all possible use a disinfectant on the area.

The person who was injured should seek medical assistance for tests to be sure that they have not been affected.

Learn more about infectious material at brainly.com/question/10928952

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A cantilever beam AB of length L has fixed support at A and spring support at B.

atroni [7]

The force in the spring will be $F =\dfrac{KPl^3}{3EI}$ .

The deflection of the beam will be $\rho$ = $0.15(\dfrac{KPL^3}{3EI})$

<h3>What is a cantilever beam?</h3>

A rigid, horizontally extending structural member known as a cantilever is supported at only one end. Typically, it extends from a solidly affixed flat vertical surface, such as a wall.

Given that:-

A cantilever beam AB of length L has fixed support at A and spring support at B.
The spring behaves in a linearly elastic manner with stiffness k. If a concentrated load P is applied at B.

The spring force will be calculated as:-

$F = kx$

Deflection will be given by:-

$x = \dfrac{PL^3}{3EI}$

The spring force will be calculated by:-

$F = \dfrac{KPL^3}{3EI}$

The deflection of the beam will be given as:-

$\rho = \dfrac{0.15KPL^3}{3EI}$

Therefore the force in the spring will be $F =\dfrac{KPl^3}{3EI}$ ..The deflection of the beam will be $\rho$ = $0.15(\dfrac{KPL^3}{3EI})$

To know more about Cantilever beam follow

brainly.com/question/16791806

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7 0

2 years ago

A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 4 MPa in the boiler and 20

viktelen [127]

Answer:

a) 69,630KW

b) 203 KW

Explanation:

The data obtained from Tables A-4, A-5 and A-6 is as follows:

$h_{1} = h_{f,@20KPa} = 251.42 KJ/kg\\v_{1} = v_{f,@20KPa} = 0.001017 KJ/kgK\\\\w_{p,in} = v_{1} * (P_{2} - P_{1})\\w_{p,in} = (0.001017)*(4000-20)\\\\w_{p,in} = 4.05 KJ/kg\\\\h_{2} = h_{1} - w_{p,in} \\h_{2} = 251.42 + 4.05\\\\h_{2} = 255.47KJ/kg\\\\P_{3} = 4000KPa\\T_{3} = 700 C\\s_{3} = 7.6214 KJ/kgK\\\\h_{3} = 3906.3 KJ/kg\\\\P_{4} = 20 KPa\\s_{3} = s_{4} = 7.6214KJ/kgK\\s_{f} = 0.8320 KJ/kgK\\s_{fg} = 7.0752 KJ/kgK\\\\$

$x_{4} = \frac{s_{4} - s_{f} }{s_{fg} } \\\\x_{4} = \frac{7.6214-0.8320}{7.0752} = 0.9596\\\\h_{f} = 251.42KJ/kg \\h_{fg} = 2357.5KJ/kg \\\\h_{4} = h_{f} + x_{4}*h_{fg} = 251.42 + 0.9596*2357.5 = 2513.7KJ/kg\\\\$

The power produced and consumed by turbine and pump respectively are:

$W_{T,out} = flow(m) *(h_{3} - h_{4}) \\W_{T,out} = 50 *(3906.3-2513.7)\\\\W_{T,out} = 69,630 KW\\\\W_{p,in} = flow(m) *w_{p,in} = 50*4.05 = 203 KW$

7 0

3 years ago

Hey, I have a question, I was thinking that if you have engineering skills or drawing skill you could help me to start a project

gayaneshka [121]

Answer

Dont have one;(

Explanation:

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3 years ago

Solar energy stored in large bodies of water, called solar ponds, is being used to generate electricity. If such a solar power p

fgiga [73]

Answer: 1.137*10^7 Btu/h.

Explanation:

Given data:

Efficiency of the plant = 4.5percent

Net power output of the plant = 150kw

Solution:

The required collection rate

QH = W/n

= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.

= 3333.333 *3412.152Btu/h.

= 11373840 Btu/h

= 1.137*10^7 Btu/h.

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3 years ago

Whats the difference between GeForce GTX 1060 and Geforce GTX 3060? Is there any big changes to FPS and other settings?

ZanzabumX [31]

Answer:

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Explanation:

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3 years ago

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