I have to find the critical points of this function of two variables
4%2By%5E4-16%28x%2By%29%5E2%5C%5C" id="TexFormula1" title="\\f(x,y)=x^4+y^4-16(x+y)^2\\" alt="\\f(x,y)=x^4+y^4-16(x+y)^2\\" align="absmiddle" class="latex-formula">, for this we use the gradient method which equals to ZERO the first partial derivatives. After clearing both equations we should find the following points: P (__, 0), Q (4, __), R (4, __) My problem is that I cannot clear the following equations:
Is there any way to deal with these equations of degree n?
Is there any way to deal with these equations of degree n?
1 answer:
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Complete Question
Air at 40C flows over a 2 m long flat plate with a free stream velocity of 7m/s. Assume the width of the plate (into the paper) is 0.5 m. If the plate is at a co temperature of 100C,find:
The total heat transfer rate from the plate to the air
Answer:
Explanation:
From the question we are told that:
Air Temperature
Length
Velocity
Width
Constant temperature
Generally the equation for Total heat Transfer is mathematically given by
Where
h=Convective heat transfer coefficient
Therefore
Answer:
Heat required =7126.58 Btu.
Explanation:
Given that
Mass m=20 lb
We know that
1 lb =0.45 kg
So 20 lb=9 kg
m=9 kg
Ice at -15° F and we have to covert it at 200° F.
First ice will take sensible heat at up to 32 F then it will take latent heat at constant temperature and temperature will remain 32 F.After that it will convert in water and water will take sensible heat and reach at 200 F.
We know that
Specific heat for ice
Latent heat for ice H=336 KJ/kg
Specific heat for ice
We know that sensible heat given as
Heat for -15F to 32 F:
Q=858.69 KJ
Heat for 32 Fto 200 F:
Q=6330.74 KJ
Total heat=858.69 + 336 +6330.74 KJ
Total heat=7525.43 KJ
We know that 1 KJ=0.947 Btu
So 7525.43 KJ=7126.58 Btu
So heat required to covert ice into water is 7126.58 Btu.