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mylen [45]
3 years ago
12

I have to find the critical points of this function of two variables

4%2By%5E4-16%28x%2By%29%5E2%5C%5C" id="TexFormula1" title="\\f(x,y)=x^4+y^4-16(x+y)^2\\" alt="\\f(x,y)=x^4+y^4-16(x+y)^2\\" align="absmiddle" class="latex-formula">, for this we use the gradient method which equals to ZERO the first partial derivatives. After clearing both equations we should find the following points: P (__, 0), Q (4, __), R (4, __) My problem is that I cannot clear the following equations:
\\1)  4x^{3} -32x -32y = 0\\2) 4y^{3} -32x-32y = 0
Is there any way to deal with these equations of degree n?
Engineering
1 answer:
liraira [26]3 years ago
4 0

Answer:

no i dont think there is

Explanation:

because theres not

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Gas is kept in a 0.1 m diameter cylinder under the weight of a 100 kg piston that is held down by a spring with a stiffness k =
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Answer:

The spring is compressed by 0.275 meters.

Explanation:

For equilibrium of the gas and the piston the pressure exerted by the gas on the piston should be equal to the sum of  weight of the piston and the force the spring exerts on the piston

Mathematically we can write

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we know that

Force_{pressure}=Pressure\times Area=300\times 10^{3}\times \frac{\pi \times 0.1^2}{4}=750\pi Newtons

Weight_{piston}=mass\times g=100\times 9.81=981Newtons

Now the force exerted by an spring compressed by a distance 'x' is given by Force_{spring}=k\cdot x=5\times 10^{3}\times x

Using the above quatities in the above relation we get

5\times 10^{3}\times x+981=750\pi \\\\\therefore x=\frac{750\pi -981}{5\times 10^{3}}=0.275meters

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