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3 years ago

The terms batten seam, standing seam, and flat seam all describe types of:

Engineering

1 answer:

abruzzese [7]3 years ago

5 0

Answer:

 (A) architectural sheet metal roofing

Explanation:

By the name itself we can judge that the 'Architectural sheet metal roofing' is a kind of metal roofing.

And these type of metal roofing is primarily used for small and big houses, small buildings and as well as in a building that is for commercial use they can be totally flat as well as little bit sloped.

And the words similarly like batten and standing seam, and flat seam all tells us that these are the types of architectural sheet metal roofing.

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Since the application can be the prospective employers first impression, it is important to a. always answer questions truthfull

loris [4]

Answer:

Definitely D

Explanation:

You should do all of those things in an application.

7 0

4 years ago

Read 2 more answers

C+ Write a program that converts degrees Fahrenheit to Celsius using the following formula. degreesC = 5(degreesF – 32)/9

Yanka [14]

Answer:

Written in C++

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

float degreeC, degreeF;

cout<<"Degree Fahrenheit: ";

cin>>degreeF;

degreeC = 5 * (degreeF - 32)/9;

cout<<"Degree Celsius: "<<degreeC<<" C";

return 0;

}

Explanation:

The question requests that input should be in degree Fahrenheit

Declare all necessary variables

float degreeC, degreeF;

Prompt user for input in degrees Fahrenheit as stated in the question

cout<<"Degree Fahrenheit: ";

Get User Input

cin>>degreeF;

Convert degree Fahrenheit to Celsius

degreeC = 5 * (degreeF - 32)/9;

Display output

cout<<"Degree Celsius: "<<degreeC<<" C";

4 0

3 years ago

The surface of an object is the texture value appearance or function

maksim [4K]

Texture value appearance

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3 years ago

A car engine with a thermal efficiency of 33% drives the air-conditioner unit (a refrigerator) besides powering the car and othe

fgiga [73]

Answer:

The rate of fuel required to drive the air conditioner $Q_h = 6.061 kW$

The flow rate of the cold air is $\r m = 0.30765 kg/s$

Explanation:

From this question we are told that

The efficiency is $\eta = 33$ % = 0.33

Temperature for the hot day is $T_h = 35^oC = 308 K \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (35+273)$

Temperature after cooling is $T_c = 5^oC = 278K$

The input power is $P_{in} = 2kW$

The rate of fuel required to drive the air conditioner can be mathematically represented as

$Q_h = \frac{P_{in}}{\eta}$

$= \frac{2}{0.33} = 6.061 kW$

From the question the air condition is assumed to be half as a Carnot refrigeration unit

This can be Mathematically interpreted in terms of COP(coefficient of performance) as

$\beta_{air} = 0.5 \beta$

where $\beta$ denotes COP and is mathematically represented as

$\beta = \frac{Q_c}{P_{in}}$

= > $Q_c = \beta P_{in}$

Where $Q_c$ is the rate of flue being burned for cold air to flow

Now if the COP of a Carnot refrigerator is having this value

$\beta_{Carnot } = \frac{T_c}{T_h - T_c}$

$= \frac{278}{308-278}$

$\beta_{Carnot} = 9.267\\$

Then

$\beta_{air} = 0.5 * 9.2667$

$= 4.6333$

Now substituting the value of $\beta$ to solve for $Q_c$

$Q_c = \beta P_{in}$

$= 4.6333 *2$

$9.2667kW$

The equation for the rate of fuel being burned for the cold air to flow

$Q_c = \r mc_p \Delta T$

Making the flow rate of the cold air

$\r m = \frac{Q_c}{c_p \Delta T}$

$= \frac{9.2667}{1.004}* (308 - 278)$

$= 0.30765 kg/s$

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3 years ago

Technician A says that weld-on dent removal attachments may be used on a steel panel.

spin [16.1K]

Answer:

sjasfjajfhajshfdff

Explanation:

7 0

3 years ago