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andrew11 [14]
3 years ago
9

Write a loop to print all elements in hourly_temperature. Separate elements with a -> surrounded by spaces. Sample output for

the given program with input: '90 92 94 95' 90 -> 92 -> 94 -> 95 Note: 95 is followed by a space, then a newline

Engineering
1 answer:
ELEN [110]3 years ago
6 0

The answer & explanation for this question is given in the attachment below.

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What does carbon addition to iron do, what does it produce, how does it change properties, what are its reflections? Describe in
NISA [10]

Answer:

Demire karbon ilavesi ne yapar, ne değiştirir, özellikleri nasıl değiştirir, yansımaları nelerdir? Grafiklerde kullanarak detaylı olarak açıklayın. HMK brainly.com/app/profile/7139574 takip et!!!!  

8 0
3 years ago
A rectangular region ABCD is to be built inside a semicircle of radius 10 m with points A and B on the line for the diameter and
Talja [164]

Answer:A rectangular region ABCD is to be built inside a semicircle of radius 10 m with points A and B on the line for the diameter and points C and D on the semicircle with CD parallel to AB. The objective is to find the height h * that maximizes the area of ABCD.

Formulate the optimization problem.

Explanation:A rectangular region ABCD is to be built inside a semicircle of radius 10 m with points A and B on the line for the diameter and points C and D on the semicircle with CD parallel to AB. The objective is to find the height h * that maximizes the area of ABCD.

Formulate the optimization problem.

7 0
3 years ago
It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 630 MPa. Calc
ratelena [41]

Answer:

The answer is below

Explanation:

Given that:

Diameter (D) = 0.03 mm = 0.00003 m, length (L) = 2.4 mm = 0.0024 m, longitudinal tensile strength (\sigma_{cd})=630\ MPa = 630*10^6\ Pa, Fracture strength

(\sigma_f)=5100\ MPa=5100*10^6\ Pa,fiber-matrix\ stres(\sigma_m)=17.5\ MPa=17.5*10^6\ Pa,matrix\ strength=\tau_c=17\ MPa=17 *10^6\ Pa

a) The critical length (L_c) is given by:

L_c=\sigma_f*(\frac{D}{2*\tau_c} )=5100*10^6*\frac{0.00003}{2*17*10^6}=0.0045\ m=4.5\ mm

The critical length (4.5 mm) is greater than the given length, hence th composite can be produced.

b) The volume fraction (Vf) is gotten from the formula:

\sigma_{cd}=\frac{L*\tau_c}{D}*V_f+\sigma_m(1-V_f)\\\\V_f=\frac{\sigma_{cd}-\sigma_{m}}{\frac{L*\tau_c}{D}-\sigma_{m}}  \\\\Substituting:\\\\V_f=\frac{630*10^6-17.5*10^6}{\frac{0.0024*17*10^6}{0.00003} -17.5*10^6} \\\\V_f=0.456

6 0
2 years ago
You are traveling upstream on a river at dusk. You see a buoy with the number 5 and a flashing green light . What should you do?
nalin [4]

Answer:

please give brainliest my brother just got the corona virus

Explanation:

this is my brothers account he wants to get 5 brainliest

8 0
3 years ago
Discuss the difference between the observed and calculated values. Is this error? If yes, what is the source?
Scrat [10]

Answer and Explanation:

In any experiment, the observed values are the actual values obtained in any experiment.

The calculated values are the values that are measured by using the observed values in a formula.

The observed values are primary values whereas the calculated values are the secondary values as calaculations are made using observed values.

Yes, if the observed values are of low accuracy.

The values should be recorded with proper care and attention in order to avoid any error.

8 0
3 years ago
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