Answer:
13.2 miles
Step-by-step explanation:
To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.
(5.5 + 3.5)² + b² = 15²
9² + b² = 15²
81 + b² = 225
b² = 144
b = 12
Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).
5.5² + 12² = c²
30.25 + 144 = c²
174.25 = c²
13.2 ≈ c
Therefore, the shortest route from Chenoa to Robertsville is about 13.2 miles.
That's easy 172.1 times 10 with the exponent of 7
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first and second part put 0.75, then multiply 0.75 by 2 to get 1.50, then write in the third part 1 and 1/2
hope this helps
<span>For a rotation of 90o: (x, y) ⇒ (–y, x)
T(3,4) ⇒⇒⇒ T'(-4,3)
W(-2,-1) ⇒⇒⇒ W'(1,-2)
x(-3,3) ⇒⇒⇒ x'(-3,-3)
see the attached figure
</span>
Answer:
3(x + 4) = 3(x) + 3(4)
3(x + 4) = 3x + 12
3x + 12 = 3x + 12
Subtract 12 from both sides
3x + 12 - 12 = 3x + 12 - 12
3x = 3x
3x - 3x = 3x - 3x
= 0
