Question

The legs if an isosceles triangle are (3x^2+4x+2) inches and the base is (4x-5) inches. Find the perimeter of the triangle

Answer 1

Answer:

$P=(6x^2+12x-1)\ in$

Step-by-step explanation:

we know that

An isosceles triangle has two equal sides and two equal angles

so

The perimeter of triangle is equal to

$P=2(3x^2+4x+2)+(4x-5)$

Eliminate parenthesis

$P=6x^2+8x+4+4x-5$

Combine like terms

$P=(6x^2+12x-1)\ in$