Answer
The steel ball will be caught up in between the mercury and water medium.
Step-by-step explanation:
- Mercury with a density of 13546 kg/m^3
- water with a density of 1000 kg/m^3
- Steel with a density of 8050 kg/m^3
From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.
The steel ball will be caught in between both mixtures as the density of steel is 8050 kg/m^3.Which is more than Water but less than Mercury.
Answer: 36
Step-by-step explanation:
11 x 2= 22 ÷ 2= 11
10 x 5= 50÷ 2= 25
11+25= 36
Since J is the midpoint of HK, that means HK is split into two sections HJ and JK that are the same length.
1) You are told that the m<span>easure of segment HJ = 9x-2 and that of segment JK = 4x+13. Since you also know they are equal lengths, you can set these equations equal to each other to find the value of x!
HJ = JK
</span>9x-2 = 4x+13
5x = 15
x = 3
2) Now you know x = 3. Plug that into your given equations for HJ and JK to find the length of each segment (or a shortcut would be to find one of them, and then you also know the other is the same length. I'm doing both, just to make sure I don't make a silly mistake!):
HJ = <span>9x-2
</span>HJ = 9(3) - 2
HJ = 27 - 2
HJ = 25
JK = 4x + 13
JK = 4(3) + 13
JK = 12 + 13
JK = 25
3) Finally, the length of HK is just the length of HJ + JK, or HK = 25 + 25 = 50.
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Answer: HJ = 25, JK = 25, HK = 50
In order they make 20$/hr, 5$/h, 10$/hr, and 30$/hr. The last one makes the most by far!
Hi there!
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I believe your answer is:
4
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Here’s why:
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- I am assuming that the fraction is supposed to be the exponent.
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![64^{\frac{1}{3}}\\--------\\\rightarrow \text{Recall the exponent rule: } a^{\frac{m}{n}}=(\sqrt[n]{a})^m\\\\\\\rightarrow \sqrt[3]{64}\\\\\rightarrow \boxed{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C--------%5C%5C%5Crightarrow%20%5Ctext%7BRecall%20the%20exponent%20rule%3A%20%7D%20a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%28%5Csqrt%5Bn%5D%7Ba%7D%29%5Em%5C%5C%5C%5C%5C%5C%5Crightarrow%20%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5C%5Crightarrow%20%20%5Cboxed%7B4%7D)
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Hope this helps you. I apologize if it’s incorrect.
