All categories

3 years ago

Please help with this question

Physics

2 answers:

lukranit [14]3 years ago

7 0

Answer:

the type of force is Unbalanced force;

As upward force is not equal to downward force.

kompoz [17]3 years ago

3 0

The answer is unbalanced because the numbers 100n and 300n don’t equal each other. If the answer was balanced the numbers would have to equal each other. Also, the answer net force would only be the answer if we were adding the numbers. I hope this helped you! :)

You might be interested in

14 How many electrons are in the atom pictured? 9 p* 10 nº

yKpoI14uk [10]

Answer:

9 electrons

Explanation:

The structure has 9 protons and hence the number of electrons equals the number of protons that's why it is said to be electrical neutral

7 0

3 years ago

Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes s

romanna [79]

Answer:

An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.

Explanation:

Hope this helps

May I get braineist pls?

5 0

3 years ago

A sanding disk with rotational inertia 2.0 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit

Inessa05 [86]

Answer

Given,

Rotational inertia = 2.0 x 10-3 kg·m²

Torque = 11 N.m

time, t = 19 ms

a) Angular momentum

$\tau = \dfrac{\Delta L}{\Delta t}$

L is angular momentum

$\Delta L = \tau \Delta t$

$\Delta L = 11\times 19 \times 10^{-3}$

$\Delta L = 0.209\ Kg m^2/s$

b) Angular velocity

We know.

$L = I \omega$

$\omega = \dfrac{L}{I}$

$\omega = \dfrac{0.209}{2\times 10^{-3}}$

$\omega = 104.5\ rad/s$

4 0

3 years ago

You push a box out of a carpeted room and along a hallway with a waxed linoleum floor. While pushing the crate 3 m out of the ro

mylen [45]

The total work done is equal to 134 J.

The work formula is characterized as the multiplication of the force performed and the distance in which the movement was performed, so that:

$W = F \times d$