The chewing muscle, the masseter, is one of the strongest in the human body. It is attached to the mandible (lower jawbone) as s
hown in figure
(A) The jawbone is pivoted about a socket just in front of the auditory canal. The forces acting on the jawbone are equivalent to those acting on the curved bar in figure
(B) In figure a, a skull is shown. The lower jaw is labeled "Mandible".
A muscle labeled "Masseter" connects the back of the lower jaw to the upper part of the skull. In figure b, The jawbone is modeled by a curved bar. The left portion of the bar is horizontal, the right portion bends diagonally up and to the right. Three forces act on the bar: Vector T points directly upward at the point where the bar bends. Vector FC acts directly downward at the left end of the bar, a horizontal distance of 7.50 cm from vector T. Vector T points directly upward at the point where the bar bends. Vector R acts directly downward at the right end of the bar, a horizontal distance of 3.50 cm from vector T. F C is the force exerted by the food being chewed against the jawbone, T is the force of tension in the masseter, and R is the force exerted by the socket on the mandible. Find T and R (in N) for a person who bites down on a piece of steak with a force of 56.6 N. magnitude of R N
(A) The jawbone is pivoted about a socket just in front of the auditory canal. The forces acting on the jawbone are equivalent to those acting on the curved bar in figure
(B) In figure a, a skull is shown. The lower jaw is labeled "Mandible".
A muscle labeled "Masseter" connects the back of the lower jaw to the upper part of the skull. In figure b, The jawbone is modeled by a curved bar. The left portion of the bar is horizontal, the right portion bends diagonally up and to the right. Three forces act on the bar: Vector T points directly upward at the point where the bar bends. Vector FC acts directly downward at the left end of the bar, a horizontal distance of 7.50 cm from vector T. Vector T points directly upward at the point where the bar bends. Vector R acts directly downward at the right end of the bar, a horizontal distance of 3.50 cm from vector T. F C is the force exerted by the food being chewed against the jawbone, T is the force of tension in the masseter, and R is the force exerted by the socket on the mandible. Find T and R (in N) for a person who bites down on a piece of steak with a force of 56.6 N. magnitude of R N
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Answer:
The value of the distance is .
Explanation:
The velocity of a particle(v) executing SHM is
where, is the angular frequency,
is the amplitude of the oscillation and
is the displacement of the particle at any instant of time.
The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., .
The maximum velocity() is
Divide equation (1) by equation(2).
Given, and
. Substitute these values in equation (3).