The chewing muscle, the masseter, is one of the strongest in the human body. It is attached to the mandible (lower jawbone) as s
hown in figure
(A) The jawbone is pivoted about a socket just in front of the auditory canal. The forces acting on the jawbone are equivalent to those acting on the curved bar in figure
(B) In figure a, a skull is shown. The lower jaw is labeled "Mandible".
A muscle labeled "Masseter" connects the back of the lower jaw to the upper part of the skull. In figure b, The jawbone is modeled by a curved bar. The left portion of the bar is horizontal, the right portion bends diagonally up and to the right. Three forces act on the bar: Vector T points directly upward at the point where the bar bends. Vector FC acts directly downward at the left end of the bar, a horizontal distance of 7.50 cm from vector T. Vector T points directly upward at the point where the bar bends. Vector R acts directly downward at the right end of the bar, a horizontal distance of 3.50 cm from vector T. F C is the force exerted by the food being chewed against the jawbone, T is the force of tension in the masseter, and R is the force exerted by the socket on the mandible. Find T and R (in N) for a person who bites down on a piece of steak with a force of 56.6 N. magnitude of R N
(A) The jawbone is pivoted about a socket just in front of the auditory canal. The forces acting on the jawbone are equivalent to those acting on the curved bar in figure
(B) In figure a, a skull is shown. The lower jaw is labeled "Mandible".
A muscle labeled "Masseter" connects the back of the lower jaw to the upper part of the skull. In figure b, The jawbone is modeled by a curved bar. The left portion of the bar is horizontal, the right portion bends diagonally up and to the right. Three forces act on the bar: Vector T points directly upward at the point where the bar bends. Vector FC acts directly downward at the left end of the bar, a horizontal distance of 7.50 cm from vector T. Vector T points directly upward at the point where the bar bends. Vector R acts directly downward at the right end of the bar, a horizontal distance of 3.50 cm from vector T. F C is the force exerted by the food being chewed against the jawbone, T is the force of tension in the masseter, and R is the force exerted by the socket on the mandible. Find T and R (in N) for a person who bites down on a piece of steak with a force of 56.6 N. magnitude of R N
1 answer:
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Answer:
<u>6 bulbs</u> are needed to illuminate the room.
Explanation:
Given:
Measurement of kitchen (A) = 10 ft by 10 ft = 100 sq. ft
Number of footcandles (n) = 50
Lumens emitted by 1 bulb = 834
Number of bulbs (N) = ?
We are also given,
1 foot candle = 1 lumen/sq. ft
So, 50 foot candles = 50 lumens/sq. ft
Now, for an area of 1 sq. ft 50 lumens are emitted.
So, for an area of 100 sq. ft, lumens emitted = 50 × 100 = 5000 lumens
Now, one bulb emits = 834 lumes
Therefore, number of bulbs required for emitting 5000 lumens is given as:
So, 6 bulbs are needed to illuminate the room.
<h2>Answer: 13.61 N/m</h2>
Hooke's law establishes that the elongation of a spring is directly proportional to the modulus of the force applied to it, <u>as long as the spring is not permanently deformed</u>:
(1)
Where:
is the elastic constant of the spring. The higher its value, the more work it will cost to stretch the spring.
is the length of the spring without applying force.
is the length of the spring with the force applied.
According to this, we have a spring where only the force due gravity is applied.
In other words, the force applied is the weigth of the block:
(2)
Where is the mass of the block and
is the gravity acceleration.
(3)
(4)
Knowing the force applied and
and
, we can substitute the values in equation (1) and find
:
(5)
(6)
<u>Finally:</u>