Answer:
The angle through which the wheel turned is 947.7 rad.
Explanation:
initial angular velocity,
= 33.3 rad/s
angular acceleration, α = 2.15 rad/s²
final angular velocity,
= 72 rad/s
angle the wheel turned, θ = ?
The angle through which the wheel turned can be calculated by applying the following kinematic equation;

Therefore, the angle through which the wheel turned is 947.7 rad.
Find the electric flux and the disp at t=0.50ns
<span>Given: </span>
<span>Resistor R = 160 Ω </span>
<span>Voltage ε = 22.0 V </span>
<span>Capacitor C = 3.10 pF = 3.10 * 10^-12 F </span>
<span>time t = 0.5 ns = 0.5 * 10^-9 s </span>
<span>ε0 = 8.85 * 10^-12 </span>
<span>Solution: </span>
<span>ELECTRIC FLUX: </span>
<span>Φ = Q/ε0 </span>
<span>we have ε0, we need to find Q the charge </span>
<span>STEP 1: FIND Q </span>
<span>Q = C ε ( 1 - e^(-t/RC) ) </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 1 - 0.365 } </span>
<span>Q = { 3.10 * 10^-12 } { 22.0 } { 0.635 } </span>
<span>Q = 43.31 * 10^-12 C </span>
<span>STEP 2: WE HAVE Q AND ε0 > >>> SOLVE FOR ELECTRIC FLUX >>> </span>
<span>Φ = Q/ε0 </span>
<span>Φ = { 43.31 * 10^-12 C } / { ε0 = 8.85 * 10^-12 } </span>
<span>Φ = 4.8937 = 4.9 V.m </span>
<span>DISPLACEMENT CURRENT </span>
<span>we use the following equation: </span>
<span>I = { ε / R } { e^(-t/RC) } </span>
<span>I = { 22 / 160 } { e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } </span>
<span>I = { 0.1375 } { 0.365 } </span>
<span>I = 0.0502 A = 0.05 A </span>
Answer:
The electric potential will be "259.695 volt".
Explanation:
In the given question, the figure is not provided. Below is the attached figure given.
Given:





Now,
At point P, the electric potential will be:
⇒ 
By putting values, we get
⇒ ![=9\times 10^9 [\frac{6.39\times 10^{-9}}{0.40} +\frac{3.22\times 10^{-9}}{0.25} ]](https://tex.z-dn.net/?f=%3D9%5Ctimes%2010%5E9%20%5B%5Cfrac%7B6.39%5Ctimes%2010%5E%7B-9%7D%7D%7B0.40%7D%20%2B%5Cfrac%7B3.22%5Ctimes%2010%5E%7B-9%7D%7D%7B0.25%7D%20%5D)
⇒ 
Weight of the bus= mass x acceleration due to gravity = 1021x9.8 = 10005.8 N. Hope it helps.