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Misha Larkins [42]
3 years ago
8

A nuclear power plant operates at 79 percent of its maximum theoretical (Carnot) efficiency between temperatures of 700° and 330

°C. If the plant produces electric energy at the rate of 1.3 GW, how much exhaust heat is discharged per hour?
Physics
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

Explanation:

T₁ = 700 + 273 = 973 k

T₂ = 330 + 273 = 603 k

Theoretical efficiency = T₁ - T₂ / T₁

= (973 - 603) / 973

= .38 OR 38%

Operating efficiency = .79 x 38

= 30.02 %

Heat input Q₁ , Heat output to sink Q₂ , conversion into power = Q₁ - Q₂

given Q₁ - Q₂ = 1.3 x 10⁹ W

efficiency = Q₁ - Q₂  /  Q₁

Q₁ - Q₂  /  Q₁ = 30.02 / 100

100Q₁ - 100Q₂ = 30.02Q₁

69.98 Q₁  = 100Q₂

Q₁  = 1.429 Q₂

Putting this in the relation

Q₁ - Q₂ = 1.3 x 10⁹ W

1.429Q₂ - Q₂ = 1.3 x 10⁹ W

.429Q₂ = 1.3 x 10⁹

Q₂  = 3.03 x 10⁹W

= 3.03 GW.

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E_{EL}=\frac{1}{2}kx^2

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In this situation, the spring has been released, so it returns to its natural position, so its elastic potential energy is zero. The toy is also stationary, since it is at its top position, where its velocity is zero, so its kinetic energy is also zero. However, the toy is now at a certain height h above the spring, so it has gravitational potential energy given by:

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In this situation, the toy is falling: so, it is moving with a certain speed v, so it has kinetic energy given by

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EXPLANATION :

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