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Solnce55 [7]
4 years ago
6

During physical science, Ms. Greene challenged her students to produce an energy transformation. James and Jill wrapped a 4-inch

nail with a coil of fifty turns of wire. They connected one end of the coil to one terminal of a knife switch. They connected the other terminal of the knife switch to the battery. Finally, they connected the end of the coil to the other terminal of the battery. James held the tip of a 1-inch nail near the flat end of the 4-inch nail. Jill closed the knife switch quickly and then opened it. The 1-inch nail was pulled toward the 4-inch nail.
What is the BEST explanation of why the nail moved?
A) Electrical energy was converted to mechanical energy in the 1-inch nail.
B) The 4-inch nail became an electromagnet and the magnetic force attracted the 1-inch nail.
C) The electric current in the 4-inch nail was converted to mechanical energy in the 1-inch nail.
D) The 4-inch nail had a positive charge and the 1-inch nail had a negative charge. Opposites attracted.
Physics
1 answer:
IrinaK [193]4 years ago
8 0

Answer: Its <u>B</u> I got it right on USAtestp

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PART A)

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here we have

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q_2 = -1.6 \times 10^{-19} C

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now we have

V = \frac{Ke}{r} - \frac{Ke}{r}

V = 0

Now work done to move another charge from infinite to origin is given by

W = q(V_f - V_i)

here we will have

W = e(0 - 0) = 0

so there is no work required to move an electron from infinite to origin

PART B)

Initial potential energy of electron

U = \frac{Kq_1e}{r_1} + \frac{kq_2e}{r_2}

U = \frac{9\times 10^9(-1.6\times 10^{-19}(-1.6 \times 10^{-19})}{19} + \frac{9\times 10^9(1.6\times 10^{-19}(-1.6 \times 10^{-19})}{21}

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3 years ago
A block of mass
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(a) The work done by the applied force is 26.65 J.

(b) The work done by the normal force exerted by the table is 0.

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<h3>Work done by the applied force</h3>

W = Fdcosθ

W = 14 x 2.1 x cos25

W = 26.65 J

<h3>Work done by the normal force</h3>

W = Fₙd

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W = 0 J

<h3>Work done force of gravity</h3>

The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.

<h3> Work done by the net force on the block</h3>

∑W = 0 + 26.65 J = 26.65 J

Thus, the work done by the applied force is 26.65 J.

The work done by the normal force exerted by the table is 0.

The work done by the force of gravity is 0.

The work done by the net force on the block is 26.65 J.

Learn more about work done here: brainly.com/question/8119756

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Answer:

Explanation:

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