Answer:
- See the graph attached with the vectors.
Explanation:
The exercise is to draw the corresponding vectors:
Every one is the multiplication of a scalar by a vector.
The result of multiplying a scalar by a vector is a vector with the same direction of the original vector enlarged in a factor equal to the scalar magntitude.
Thus, in a graph the resulting vector is represented with a parallel arrow and pointing in the same direction as the original vector but with a length equal to the original length multiplied by the magnitude of the scalar.
For instance, the vector 
is represented with an arrow in the same direction of 
and with twice its length.
The figure attached contains the five requested vectors using the procedure explained above.
Explanation:
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(a) <u>The</u><u> </u><u>segment</u><u> </u>A shows acceleration as velocity increases with the increase in time.
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(b) <u>The</u><u> </u><u>segment</u><u> </u>C shows the object is slowing down as the time increases in segment C, the velocity decreases and afterwards it comes to rest.
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(c) The velocity is segment B is <u>4</u><u>0</u><u>m</u><u>/</u><u>s</u><u>.</u> And in the diagram there is no change in velocity.
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(d) The acceleration of segment B is <u>zero</u><u>.</u> As there in no change in curve and it is moving with uniform velocity.
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<h2>Thank you!</h2>
Answer:
4 hrs
Explanation:
625 = 5000 (1/2)^n
625/5000 = 1/2^n
n = 3 half lives
3 half lives = 12 hours 1 half life = 4 hrs
<h3><u>Answer</u>;</h3>
B. When actin filaments are pulled toward the center of the sarcomere, the fiber shortens.
<h3><u>Explanation;</u></h3>
- <em><u>The events of muscle fiber shortening occurs with in the sacromeres in the fibers. </u></em>
- <em><u>Contraction of striated muscle fibers takes place as the sacromeres shorten as myosin heads pull on the actin filaments.</u></em>
- <em><u>Filament movement starts at the region or zone where thin and thick filaments overlap. </u></em>
- <em><u>Myofibril contains many sacromeres along its length and thuse myofibrils and muscle cells contract as the sacromeres contract.</u></em>
From what I know.. I'd say the answer is D(:
