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yaroslaw [1]
3 years ago
12

Which of the following statements is true for real gases?

Physics
2 answers:
jok3333 [9.3K]3 years ago
3 0

Answer:

A. The volume occupied by the molecules can cause an increase in pressure compared to the ideal gas.

D. As attractive forces between molecules increase, deviations from ideal behavior become more apparent at relatively low temperatures.

Explanation:

as we know by real gas equation

(P + \frac{an^2}{V^2})(V - nb) = nRT

while ideal gas equation is given as

PV = nRT

so from above formula we can say that net pressure is increased in real gas

Also we know that all real gas will close to behave like ideal gas when the pressure of the real gas is low and temperature of the gas is high

So above are the correct observations

ivolga24 [154]3 years ago
3 0

Answer: Option (D) is the correct answer.

Explanation:

In real gases, there exists force of attraction between the molecules at low temperature and high pressure. This is because at low temperature there occurs a decrease in kinetic energy of gas molecules and high pressure causes the molecules to come closer to each other.

As a result, forces of attraction increases as molecules come closer to each other and therefore, gases deviate from an ideal gas behavior.

And, at low pressure and high temperature there exists no force of attraction or repulsion between the molecules of a gas. Hence gases behave ideally at these conditions.

Thus, we can conclude that the statement as attractive forces between molecules increase, deviations from ideal behavior become more apparent at relatively low temperatures, is true for real gases.

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Kazeer [188]

Answer:

6400 W (or) 6.4 KW

Explanation:

Formula we use,

→ P = I²R

Let's solve for the power of device,

→ P = I²R

→ P = (8)² × 100

→ P = 64 × 100

→ [ P = 6400 W ]

Hence, the power is 6400 W.

5 0
2 years ago
An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to
Lana71 [14]

complete question:

An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to be 5°. What is the distance from the base of the cliff to the point on the ground? Round to the nearest foot

Answer:

a ≈  5281 ft

Explanation:

The observer at the top of a 462 ft cliff  measures the angle of depression from the top of the cliff to a point on the ground to be 5°.

The angle of depression form the top of the cliff = 5°

The 5° is outside the triangle formed . To find the angle in the triangle we have to subtract 5° from 90°.  90° - 5° = 85° Note sum of an angle on a right angle is 90°.  

using SOHCAHTOA  principle we can solve for the distance from the base of the cliff to the point on the ground(a)

tan  85° = opposite / adjacent

tan 85°  = a / 462

cross multiply

462 × tan 85° = a

a = 11.4300523 × 462

a =  5280.66  ft

a ≈  5281 ft

5 0
3 years ago
A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
dangina [55]

Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

Let m1 and v1 be the mass and velocity of the bowling ball

And m2 and v2 be the mass and velocity of the bowling pin

(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f

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V2f = 11.33 m/s

<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>

8 0
3 years ago
If you stood on a planet having a mass four times higher than Earth's mass, and a radius two times 70) lon longer than Earth's r
BigorU [14]

CHECK COMPLETE QUESTION BELOW

you stood on a planet having a mass four times that of earth mass and a radius two times of earth radius , you would weigh?

A) four times more than you do on Earth.

B) two times less than you do on Earth.

C) the same as you do on Earth

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Answer:

OPTION C is correct

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Explanation :

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F= mg.....(b)

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R = radius of the earth

From law of motion

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g= GM/R^2

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7 0
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What type of diagram is this?
FromTheMoon [43]

Answer: That’s a sankey diagram

Explanation:

5 0
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