You pull a wagon up a 100m hill at 2m/s and get in and roll down the other side of the same

1 answer:

5 0

Answer: 60 s or 1 minute

explanation: divide 100m by 2m/s = 50s then 100m by 10m/s = 10s. add the two totals up 50s + 10s and get 60s or 1 minute.

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Overcoming an object inertia always requires an

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Opposite force in the opposite.

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3 years ago

A 90kg mountain climber hangs from a nylon rope and streches it ny 25.0cm. if the rope was originally 30.0m long and it's diamet

bixtya [17]

Answer:

Explanation:

E = σ/ε = (F/A) / (ΔL/L)

E = (mg/(πd²/4) / (ΔL/L)

E = (4mg/(πd²) / (ΔL/L)

E = 4Lmg/(πd²ΔL)

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2 years ago

What is a point value for an arrow that is on two different colors?

Whitepunk [10]

It depends on what it is closest to but I would say for instance black is 5 points and red is 6 if u land on the line 5.5

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3 years ago

Sometimes when we refer to carbon dioxide we write it as CO2 what is CO2

frez [133]

C stands for carbon. The O stands for oxygen. CO2 is one carbon atom and two oxygen atoms

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3 years ago

A house is losing heat at a rate of 1600 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Exp

Setler [38]

Answer:

1600 kJ/h per K, 888.88 kJ/h per °F and 888.88kJ/h per R

Explanation:

We make use of relations between temperature scales with respect to degrees celsius:

$1 K= 1^{\circ}C+273\\1^{\circ}F= (1^{\circ}C*1.8)+32\\1 R= (1^{\circ}C*1.8)+491.67$

This means that a change in one degree celsius is equivalent to a change of one kelvin, while for a degree farenheit and rankine this is equivalent to a change of 1.8 on both scales.

So:

$\frac{Q}{\Delta T(K)}=\frac{Q}{\Delta T(^\circ C)}=1600 \frac{kJ}{h} per K\\\frac{Q}{\Delta T(^\circ F)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per ^\circ F\\\frac{Q}{\Delta T(R)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per R$

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3 years ago