Answer:
Answer:
4 ms
Explanation:
initial velocity, u = 75 m/s
final velocity, v = 0
distance, s = 15 cm = 0.15 m
Let the acceleration is a and the time taken is t.
Use third equation of motion
v² = u² + 2 a s
0 = 75 x 75 - 2 a x 0.15
a = - 18750 m/s^2
Use first equation of motion
v = u + at
0 = 75 - 18750 x t
t = 4 x 10^-3 s
t = 4 ms
thus, the time taken is 4 ms.
Explanation:
Explanation:
1.
We use the equation
h = 
, where
h is the height traveled,
g is the acceleration due to gravity and
t is the time taken to reach height h.
We can now calculate t to be
= 0.495 s
Let v be the initial velocity of the player.
The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.
v = 9.81 m/s^2 x 0.495 s = 4.85 m/s
2.
The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is
4.85 m/s / 0.3 s = 16.2 m/s^2
Answer:
The final acceleration of the car, v = 70 m/s
Explanation:
Given,
The initial velocity of the car, u = 20 m/s
The acceleration of the car, a = 10 m/s²
The time period of travel, t = 5 s
Using the I equations of motion
v = u + at
= 20 + 10(5)
= 20 + 50
= 70 m/s
Hence, the final acceleration of the car, v = 70 m/s
Explanation:
The volume of the bread decreases, making the bread appear more compact, and smaller in size. The mass stays the same, it won't change unless part of the bread is removed. The density increases, the air bubbles inside of the bread get squished down, causing the bread to be smaller, and in turn, causing it to be more solid.
I hope this helped!
Thanks!
Your friend in answering,
~Steve
The kinds of atoms in the substance and their arrangements
